CREATE TABLE T_TYPE ( T_TYPE_ID NUMBER, T_TYPE_NAME VARCHAR2(20) ); INSERT INTO T_TYPE SELECT 1, '苹果' FROM DUAL UNION ALL SELECT 2, '香蕉' FROM DUAL;
CREATE TABLE T_INFO ( T_PERSON_ID NUMBER, T_PERSON_NAME VARCHAR(20), T_TYPE_ID DECIMAL ); INSERT INTO T_INFO SELECT 1, '张三', 1 FROM DUAL UNION ALL SELECT 1, '张三', 2 FROM DUAL UNION ALL SELECT 2, '李四', 1 FROM DUAL /* 求T_INFO表中T_PERSON_ID的T_TYPE_ID在表T_TYPE中都有的人 结果是张三 */
[解决办法] SELECT A.T_PERSON_NAME FROM T_INFO A,T_TYPE B,T_TYPE C WHERE A.T_PERSON_ID=B.T_TYPE_ID AND A.T_TYPE_ID=C.T_TYPE_ID [解决办法]
select T_PERSON_NAME from t_info group by T_PERSON_NAME having count(*) = (select count(*) from t_type)