如何求第二大的记录
表如下：
求java成绩第二高的姓名？
要求：只用用一个ＳＱＬ语句。
谢谢！
[解决办法]
用分析函数
没有测试，不知道有没有错误：
select name from (select t.*,row_number() over(order by kemu desc) rn from t where kemu='JAVA') where rn=2
[解决办法]
with t as
(select 1 as ID, 'Java' as course, 'Jim' as name, '80' as score
from dual
union all
select 2 as ID, 'Java' as course, 'Lilei' as name, '90' as score
from dual
union all
select 3 as ID, 'Java' as course, 'Hanmeimei' as name, '60' as score
from dual
union all
select 4 as ID, 'C' as course, 'Tom' as name, '100' as score from dual
)
select name
from (select name,
row_number() over(partition by course order by score desc) as rn
from t
where course = 'Java')
where rn = 2;
with t as
(select 1 as ID, 'Java' as course, 'Jim' as name, '80' as score
from dual
union all
select 2 as ID, 'Java' as course, 'Lilei' as name, '90' as score
from dual
union all
select 3 as ID, 'Java' as course, 'Hanmeimei' as name, '60' as score
from dual
union all
select 4 as ID, 'C' as course, 'Tom' as name, '100' as score from dual
)
select max(score), level
from t
where course = 'Java'
connect by prior score > score
group by level
having level = 2;
select * from (select name,score from test where kemu = 'java' order by score desc) where rownum < 3
minus
select * from (select name,score from test where kemu = 'java' order by score desc) where rownum < 2
SCOTT@xp > select * from score;
ID KEMU SCORE NAME
---------- ------ ---------- ----------
1 JAVA 80 赵
2 C 100 钱
3 JAVA 60 孙
4 C 100 李
SCOTT@xp > select rownum,a.* from (select name,score,kemu from score where kemu='JAVA' order by score )a where rownum<=1;
ROWNUM NAME SCORE KEMU
---------- ---------- ---------- ------
1 孙 60 JAVA
