有谁可以实现这个查询功能
table1
ndb004 ndb005ndb006NDB007
201303026602211
20130303660102-1 103
201303036602041
201303036602061
20130303660204-1
201303036602211
201303036602041
20130303100101-1 201
在数据库里直接得到这个表
talbe2
ndb004 ndb005 ndb006
20130302660221-1
20130303660221,660204,660206,660204,660221,660204-1
sql语句
[解决办法]
----------------------------
-- Author :DBA_Huangzj(發糞塗牆)
-- Date :2013-05-28 11:42:30
-- Version:
-- Microsoft SQL Server 2008 R2 (SP1) - 10.50.2500.0 (X64)
--Jun 17 2011 00:54:03
--Copyright (c) Microsoft Corporation
--Enterprise Edition (64-bit) on Windows NT 6.1 <X64> (Build 7601: Service Pack 1, v.721)
--
----------------------------
--> 测试数据：[table1]
if object_id('[table1]') is not null drop table [table1]
go
create table [table1]([ndb004] datetime,[ndb005] int,[ndb006] int,[NDB007] int)
insert [table1]
select '20130302',660221,1,null union all
select '20130303',660102,-1,103 union all
select '20130303',660204,1,null union all
select '20130303',660206,1,null union all
select '20130303',660204,-1,null union all
select '20130303',660221,1,null union all
select '20130303',660204,1,null union all
select '20130303',100101,-1,201
--------------开始查询--------------------------
SELECT a.[ndb004] ,
STUFF(( SELECT ',' + CONVERT(VARCHAR(128),[ndb005])
FROM [table1] b
WHERE b.[ndb004] = a.[ndb004]
AND b.[ndb006] = a.[ndb006]
FOR
XML PATH('')
), 1, 1, '') '[ndb005]', a.[ndb006]
FROM [table1] a
GROUP BY a.[ndb004] ,
a.[ndb006]
----------------结果----------------------------
/*
ndb004 [ndb005] ndb006
----------------------- ---------------------------------------------------------------------------------------------------------------- -----------
2013-03-02 00:00:00.000 660221 1
2013-03-03 00:00:00.000 660102,660204,100101 -1
2013-03-03 00:00:00.000 660204,660206,660221,660204
*/
if object_id('[table1]') is not null drop table [table1]
go
create table [table1]([ndb004] datetime,[ndb005] int,[ndb006] int,[NDB007] int)
insert [table1]
select '20130302',660221,1,null union all
select '20130303',660102,-1,103 union all
select '20130303',660204,1,null union all
select '20130303',660206,1,null union all
select '20130303',660204,-1,null union all
select '20130303',660221,1,null union all
select '20130303',660204,1,null union all
select '20130303',100101,-1,201
--------------开始查询--------------------------
select ndb004,ndb005=
stuff((select ','+cast(ndb005 as varchar) from table1 where ndb004=t.ndb004 for XML path('')),1,1,''),
MIN(ndb006) ndb006
from table1 t group by ndb004
