合并,求一个查询出结果
原始数据:
字段1 字段2 字段3 字段4
01 25100135301 a 16
01 25100135301 b 12
01 60300100001 a 10
需要的结果:
字段1字段2 字段3 字段4
01 25100135301 a,b 16+12=28
01 60300100001 a 10
sql
[解决办法]
DECLARE @B TABLE(col1 VARCHAR(6),col2 varchar(60),col3 varchar(6),col4 int)
INSERT INTO @B
SELECT '01','25100135301','a',16 UNION ALL
SELECT '01','25100135301','b',12 UNION ALL
SELECT '01','60300100001','a',10
SELECT col1,col2,
STUFF(
(SELECT ', ' + CONVERT(VARCHAR(100),col3) FROM @B T1 WHERE T1.col2 = T2.col2 FOR XML PATH('')),1,1,''
) AS col3,sum(col4) col4
FROM @B T2
GROUP BY col1,col2
CREATE TABLE T_CSDN_ONE
(
ID VARCHAR(20),
COLONE VARCHAR(50),
COLTWO VARCHAR(20),
COLTHREE INT
)
INSERT INTO T_CSDN_ONE
SELECT '01','25100135301','a',16
UNION ALL
SELECT '01','25100135301','b',12
UNION ALL
SELECT '01','60300100001','a',10
DROP FUNCTION dbo.F_GetStringByColTwo
CREATE FUNCTION F_GetStringByColTwo(@COLONE AS VARCHAR(20))
RETURNS VARCHAR(20)
AS
BEGIN
DECLARE @COLTWO VARCHAR(20)
SET @COLTWO='';
SELECT @COLTWO= @COLTWO+(CASE @COLTWO WHEN '' THEN '' ELSE ',' END)+CASE COLTWO WHEN COLTWO THEN COLTWO END
FROM T_CSDN_ONE WHERE COLONE=@COLONE GROUP BY COLTWO
return @COLTWO;
END
SELECT A.COLONE,
dbo.F_GetStringByColTwo(a.COLONE)
,SUM(A.COLTHREE)FROM T_CSDN_ONE A GROUP BY A.COLONE