json 掏出之問題

2013-04-07

json 取出之問題{contents:[{productID:34,productName:SuperWidget},{productID:56,productNa

json 取出之問題


{"contents":[{"productID":34,"productName":"SuperWidget"},{"productID":56,"productName":"WonderWidget"}]}

從遠端拉取的資料


private void saveFile() {
            try {
                FileOutputStream fileOutputStream = openFileOutput("123.txt",
                        Context.MODE_PRIVATE);
                fileOutputStream.write(resource.getBytes());
                fileOutputStream.flush();
                fileOutputStream.close();
            } catch (FileNotFoundException e) {
                e.printStackTrace();
            } catch (IOException e) {
                e.printStackTrace();
            }
            Toast.makeText(JSONExampleActivity.this, "儲存成功", Toast.LENGTH_LONG).show();
        }

儲存在Internal Storage

之後讀取


 private void readFile() {
            String temp = null;
            try {
                FileInputStream fileInputStream = openFileInput("123.txt");
                int length = fileInputStream.available();
                byte[] buffer = new byte[length];
                fileInputStream.read(buffer);
                fileInputStream.close();
                temp = new String(buffer);
            } catch (FileNotFoundException e) {
                e.printStackTrace();
            } catch (IOException e) {
                e.printStackTrace();
            }
            
  
        }

請問readFile()內的temp 要如何才會被這段執行呢?
JSONArray test = temp.getJSONArray("contents");

我知道宣告錯誤

我也試過把它變成JSONObject型態但是都還是錯誤請高人指點謝謝已爬過多文

[解决办法]
JSONArray array = new JSONArray(temp);

for(int i=0;i<array.size();i++){
JSONObject obj = array.get(i);
String str = obj.getString("productID");
}

热点排行

Bad Request.

Android

json 掏出之問題