杭电ACm求数列的和2009
#include <iostream>#include<stdio.h>#include <cmath>using namespace std;int main(){ double n,m,t=0; while (cin>>n>>m&&n<10000&&m<1000) { t=0; while (m--) { t=t+n; n=sqrt(n); } printf("%.2f\n",t); }return 0;}