九度——题目1002：Grading
Grading hundreds of thousands of Graduate Entrance Exams is a hard work. It is even harder to design a process to make the results as fair as possible. One way is to assign each exam problem to 3 independent experts. If they do not agree to each other, a judge is invited to make the final decision. Now you are asked to write a program to help this process.
For each problem, there is a full-mark P and a tolerance T(<P) given. The grading rules are:
? A problem will first be assigned to 2 experts, to obtain G1 and G2. If the difference is within the tolerance, that is, if |G1 - G2| ≤ T, this problem's grade will be the average of G1 and G2.
? If the difference exceeds T, the 3rd expert will give G3.
? If G3 is within the tolerance with either G1 or G2, but NOT both, then this problem's grade will be the average of G3 and the closest grade.
? If G3 is within the tolerance with both G1 and G2, then this problem's grade will be the maximum of the three grades.
? If G3 is within the tolerance with neither G1 nor G2, a judge will give the final grade GJ.
Each input file may contain more than one test case.
Each case occupies a line containing six positive integers: P, T, G1, G2, G3, and GJ, as described in the problem. It is guaranteed that all the grades are valid, that is, in the interval [0, P].
For each test case you should output the final grade of the problem in a line. The answer must be accurate to 1 decimal place.
20 2 15 13 10 18
14.0
import java.io.BufferedInputStream;import java.util.Scanner; public class Main{ /** * @param args */ public static void main(String[] args) { Scanner cin = new Scanner(new BufferedInputStream(System.in)); int P, T, G1, G2, G3, GJ; double finalGrade; while (cin.hasNext()) { P = cin.nextInt(); T = cin.nextInt(); G1 = cin.nextInt(); G2 = cin.nextInt(); G3 = cin.nextInt(); GJ = cin.nextInt(); if (Math.abs(G1 - G2) <= T) { finalGrade = (double) (G1 + G2) / 2; } else if ((Math.abs(G3 - G1) <= T) && (Math.abs(G3 - G2) <= T)) { if (G1 > G2) { finalGrade = G1; } else { finalGrade = G2; } if (finalGrade < G3) { finalGrade = G3; } } else if (Math.abs(G3 - G1) <= T) { finalGrade = (double) (G3 + G1) / 2; } else if (Math.abs(G3 - G2) <= T) { finalGrade = (double) (G3 + G2) / 2; } else { finalGrade = GJ; } System.out.printf("%.1f\n", finalGrade); } }} /************************************************************** Problem: 1002 User: 忆、瞻 Language: Java Result: Accepted Time:180 ms Memory:17080 kb****************************************************************/