急！求一条sql语句
求一条SQL语句，如图所示，目标是通过图一达到图二的效果（先判断name的值，如果有相同的值就只取一条数据，再把name值相同的id合并起来）
[解决办法]
SELECT name ,
[id] = STUFF(( SELECT ',' + CONVERT(VARCHAR, id)
FROM tb t
WHERE name = tb.name
FOR
XML PATH('')
), 1, 1, '')
FROM tb
GROUP BY name
select [name],[id]=stuff(( select ',' +rtrim(id) from tb t2 where t1.[name]=t2.[name] for xml path('')), 1, 1, '')from tb t1
group by [name]----------------------------
-- Author :DBA_Huangzj(發糞塗牆)
-- Date :2013-03-04 16:22:45
-- Version:
-- Microsoft SQL Server 2008 R2 (SP1) - 10.50.2500.0 (X64)
--Jun 17 2011 00:54:03
--Copyright (c) Microsoft Corporation
--Enterprise Edition (64-bit) on Windows NT 6.1 <X64> (Build 7601: Service Pack 1, v.721)
--
----------------------------
--> 测试数据：[huang]
if object_id('[huang]') is not null drop table [huang]
go
create table [huang]([id] int,[NAME] varchar(6))
insert [huang]
select 1,'你好' union all
select 2,'你好' union all
select 3,'你好' union all
select 4,'我好' union all
select 5,'大家好'
--------------开始查询--------------------------
SELECT a.name ,
STUFF(( SELECT ',' + CONVERT(VARCHAR(10),id)
FROM [huang] b
WHERE b.name = a.name
FOR
XML PATH('')
), 1, 1, '') 'id'
FROM [huang] a
GROUP BY a.name
----------------结果----------------------------
/*
name id
------ ----------------------------------------------------------------------------------------------------------------
大家好 5
你好 1,2,3
我好 4
(3 行受影响)
*/