一数组 中 对象属性值 相同的 合并?
本帖最后由 html5cloud 于 2013-02-27 01:03:21 编辑
arr = [ {a:1 , b:1 , c:1}, {a:2 , b:1 , c:2}, {a:3 , b:3 , c:3},
{a:1 , b:1 , c:4}, {a:5 , b:5 , c:5}]
//变成
arr = [ {a:1,2 , b:1 , c:1,2,4}, {a:3 , b:3 , c:3}, {a:5 , b:5 , c:5}]
var unionObjectArray = function(arr, atr){
var r = [], t = {}, x, y, z;
for(var i = 0, il = arr.length; i < il; i++){
t[arr[i][atr]] = t[arr[i][atr]]
[解决办法]
[];
t[arr[i][atr]].push(i)
}
for(var p in t)if(t.hasOwnProperty(p)){
x = {};
for(var i = 0, il = t[p].length; i < il; i++){
z = arr[t[p][i]];
for(var q in z)if(z.hasOwnProperty(q)){
x[q] = null;
}
}
for(var q in x)if(x.hasOwnProperty(q)){
y = {};
for(var i = 0, il = t[p].length; i < il; i++){
z = arr[t[p][i]];
if(z[q] != null) y[z[q]] = 1;
}
for(var s in y)if(y.hasOwnProperty(s)){
if(x[q] == null)x[q] = s;
else{
x[q] = [x[q]];
x[q].push(s)
}
}
}
r.push(x)
}
t = x = y = z = null;
return r;
};
//测试：
var printObjectArray = function(arr){
var buf = [], b;
for(var i = 0, il = arr.length; i < il; i++){
buf.push("{");
b = false;
for(var p in arr[i])if(arr[i].hasOwnProperty(p)){
if(b)buf.push(',');
b = true;
buf.push(p + ":" + (arr[i][p] instanceof Array ? "[" + arr[i][p] + "]" : arr[i][p]))
}
buf.push("}<br>")
}
document.write(buf.join(''));
},
arr = [
{a:1 , b:1 , c:1},
{a:2 , b:1 , c:2},
{a:3 , b:3 , c:3},
{a:1 , b:1 , c:4},
{a:3 , b:4 , c:5}
], atrs = ['a', 'b', 'c', 'd'];
document.write("原对象数组：<br>");
printObjectArray(arr);
document.write("<br>");
for(var i = 0, il = atrs.length; i < il; i++){
document.write("合并属性" + atrs[i] + "后：<br>");
printObjectArray(unionObjectArray(arr, atrs[i]));
document.write("<br>");
}
