Struts2 拦截器控制jsp页面跳转
源自一个题目:
请编写一个拦截器,该拦截器可以获得用户输入的用户名这个数据,业务逻辑为逐个判断用户名中是否包含“你”,“我”,“他”三个数据,如果包含则直接返回输入页面,如果不包含则运行至PersonAction。(除代码外,要给出拦截器和Action的配置文件)
最终项目结构:

直接上源码:
login.jsp:
<%@ page language="java" pageEncoding="gb2312"%><!DOCTYPE HTML PUBLIC "-//W3C//DTD HTML 4.01 Transitional//EN"><%@ taglib prefix="s" uri="/struts-tags" %><html><body><s:form action="Person"><s:textfield name="username" label="用户名"/><s:submit value="登录" align="center"/></s:form></body></html>
PersonInterceptor.java:
package com.intercept;import java.util.Map;import com.opensymphony.xwork2.ActionInvocation;import com.opensymphony.xwork2.interceptor.AbstractInterceptor;public class PersonInterceptor extends AbstractInterceptor{public String intercept(ActionInvocation ai)throws Exception{ Map<String, Object> map=ai.getInvocationContext().getParameters(); String[] username = (String[]) map.get("username"); if(username[0].indexOf("你")==-1&&username[0].indexOf ("我")==-1&& username[0].indexOf ("他")==-1){ String result=ai.invoke(); return result; }else{ return "input"; }}}注:这是拦截器类,注意获取jsp传值的方法以及intercept方法返回值。
struts.xml:
<?xml version="1.0" encoding="gb2312"?><!DOCTYPE struts PUBLIC "-//Apache Software Foundation//DTD Struts Configuration 2.0//EN""http://struts.apache.org/dtds/struts-2.0.dtd"><struts><constant name="struts.i18n.encoding" value="gb2312"/><package name="LanJieQi" extends="struts-default"><interceptors><interceptor name="intercept" class="com.intercept.PersonInterceptor"></interceptor></interceptors><action name="Person" class="com.action.PersonAction"><result name="input">/jsp/login.jsp</result><result name="success">/jsp/success.jsp</result> <interceptor-ref name="intercept"></interceptor-ref> <interceptor-ref name="defaultStack"></interceptor-ref></action></package></struts>
注:传值如果可能是汉字的话,在加上<constant>标签定义编码格式。默认拦截器"defaultStack"别忘了且要放在action配置的最下面,否则缺少了拦截核心。
PersonAction.java:
package com.action;import com.opensymphony.xwork2.ActionSupport;public class PersonAction extends ActionSupport {private String username;public void setUsername(String username) {this.username = username;}public String getUsername() {return username;}public String execute() throws Exception {return SUCCESS;}}
success.jsp:
<%@ page language="java" contentType="text/html; charset=GB2312"%><!DOCTYPE HTML PUBLIC "-//W3C//DTD HTML 4.01 Transitional//EN"><%@ taglib prefix="s" uri="/struts-tags"%><html><body><s:property value="username"/></body></html>
结果:
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显然结果是符合要求的,成功!