android 按两次返回键退出
// 返回键
private long exitTime = 0;
?
@Override
public boolean onKeyDown(int keyCode, KeyEvent event) {
if (keyCode == event.KEYCODE_BACK) {
if ((System.currentTimeMillis() - exitTime) > 2000) {
Toast.makeText(getApplicationContext(), "再按一次退出程序",
Toast.LENGTH_SHORT).show();
exitTime = System.currentTimeMillis();
} else {
finish();
// System.exit(0);
}
return true;
}
return super.onKeyDown(keyCode, event);
}
