java输入“算术表达式”的文本,如何计算表达式的值
java中输入输入“算术表达式”的文本,如何计算表达式的值?例如输入1+2/2+2*(3+1);如何直接给出10.
?
在动态语言中如python,groovy中,这些根本不是问题,到java语言中,就变成了一件挺难的事。我想到几个解决方案:
1)java中调用动态语言groovy,scala
利用动态语言能支持的这个特性,java集成调用下,当然能完成这个功能
2)手动自定义语言解析器,解析表达式文本,然后执行表达式
具体的做法可参考这篇文章,用解释器模式来做?http://blog.csdn.net/tnt32/article/details/7829288
3)用antlr自定义DSL
这个比较强大,antlr用来作这个有点大材小用,antlr是什么可参见:http://www.antlr.org/
参考资料:
http://www.antlr.org/wiki/display/ANTLR3/ANTLR+v3+documentation
http://www.antlr.org.cn/?出品的 《antlr教材.pdf》
?
自定义文法:
grammar D;options{output=AST;}program:statement+;statement:expression';'!;expression:multExpr(('+'^|'-' ^)multExpr)*;multExpr:atom(('*'^|'/'^)atom)*;atom:INT| '('!expression')'!;INT:'0'..'9' +;WS:(' ' |'\t' |'\n' |'\r' )+{skip();};?
然后利用antlrWorks工具,自动生成解析器:DLexer.java,,DParser.java
?
因为antlr只完成了词法、语法的识别,所以需要自己编写语义:
package org.mike;import org.antlr.runtime.ANTLRInputStream;import org.antlr.runtime.CommonTokenStream;import org.antlr.runtime.tree.BaseTree;import org.antlr.runtime.tree.Tree;//1+1*3+(1+1)*3;public class App { public static void main(String[] args) throws Exception { ANTLRInputStream input = new ANTLRInputStream(System.in); DLexer lexer = new DLexer(input); CommonTokenStream tokens = new CommonTokenStream(lexer); DParser parser = new DParser(tokens); DParser.program_return r = parser.program(); System.out.println(((BaseTree) r.getTree()).toStringTree()); BaseTree tree = (BaseTree) r.getTree(); System.out.println(calcNode(tree)); } public static int calcNode(Tree tree) { if (tree.getChildCount() == 0) { return Integer.parseInt(tree.getText()); } if (tree.getChildCount() != 2) { throw new RuntimeException("node " + tree.getText() + "illegal expression" + "tree.getChildCount() = " + tree.getChildCount()); } int leftChildValue = calcNode(tree.getChild(0)); int rightChildVale = calcNode(tree.getChild(1)); String sign = tree.getText().trim(); return doCalc(sign, leftChildValue, rightChildVale); } private static int doCalc(String sign, int leftChildValue, int rightChildVale) { if (sign.equals("+")) { return leftChildValue + rightChildVale; } else if (sign.equals("-")) { return leftChildValue - rightChildVale; } else if (sign.equals("*")) { return leftChildValue * rightChildVale; } else if (sign.equals("/")) { return leftChildValue / rightChildVale; } throw new RuntimeException("unknown sign " + sign); }}?
运行结果
输入:1+10/5+12+(2+3)*1+1;
输出:
(+ (+ (+ (+ 1 (/ 10 5)) 12) (* (+ 2 3) 1)) 1)21
?
?
?
?