如何用sql语句查询出当月的每日数据量
表里数据如下
id time count
1 2012-12-1 02:00:00 42
1 2012-12-1 14:18:12 79
1 2012-12-10 07:15:42 112
1 2012-12-14 10:06:20 57
1 2012-12-14 11:54:10 124
1 2012-12-14 14:10:27 241
.............................
我要统计出当月每天的count数之和（比如12月1日是 42+79= 121）
当月（比如12月份有31天，我要统计出这31天每天的的count数之和）
sql 语句该怎么写？
这里有个情况，比如12月份，有31天，就是说要取出31条数据，但数据表内可能没有12月7日的数据，检索结果中也要有12月7日的记录集
sql 返回的字段应该是如下格式的
12-1 121
12-2
12-3
...
12-10 112
这样子的，谁帮忙写一个？？？
[解决办法]
select cast(time as date),sum(count) from tb group by cast(time as date)
试试看行不。
[解决办法]
--> 测试数据：[TB]
if object_id('[TB]') is not null drop table [TB]
GO
create table [TB]([id] int,[time] datetime,[count] int)
insert [TB]
select 1,'2012-12-1 02:00:00',42 union all
select 1,'2012-12-1 14:18:12',79 union all
select 1,'2012-12-10 07:15:42',112 union all
select 1,'2012-12-14 10:06:20',57 union all
select 1,'2012-12-14 11:54:10',124 union all
select 1,'2012-12-14 14:10:27',241
DECLARE @currentMonth INT
SET @currentMonth=12
DECLARE @startDate DATETIME,@endDate DATETIME
SET @startDate=DATENAME(yy,GETDATE())+'-'+RTRIM(@currentMonth)+'-01'
SET @endDate=DATEADD(dd,-1,DATEADD(mm,1,@startDate))
select DATEADD(dd,number,@startDate),SUM(ISNULL([count],0)) FROM [master].dbo.spt_values sv LEFT JOIN tB t ON CONVERT(VARCHAR(10),t.[time],120)=CONVERT(VARCHAR(10),DATEADD(dd,number,@startDate),120)
WHERE sv.[type]='p' AND DATEADD(dd,number,@startDate)<@endDate
GROUP BY DATEADD(dd,number,@startDate)
ORDER BY 1 ASC
drop table [TB]
[解决办法]
--模拟数据表
create table [TB]([id] int,[time] datetime,[count] int)
--添加模拟数据
insert [TB]
select 1,'2012-12-01 02:00:00',42 union all
select 1,'2012-12-01 14:18:12',79 union all
select 1,'2012-12-10 07:15:42',112 union all
select 1,'2012-12-14 10:06:20',57 union all
select 1,'2012-12-14 11:54:10',124 union all
select 1,'2012-12-14 14:10:27',241
--根据日前的月份和天数分组求和，
--条件为当前的月份转换成2012-12-14 00:00:00 的时间格式
--month()、day()函数返回值为整型，故转换为字符后拼接
--数据格式为2012-12-14 00:00:00可正常运行
--如果没有12号数据则不统计
SELECT CAST(MONTH([time]) AS VARCHAR(4))+'-'+RIGHT('00'+CAST(DAY([time]) AS VARCHAR(4)),2) AS [time],
SUM([count]) AS SumCount FROM TB
WHERE CONVERT(VARCHAR(7),[time],120)=CONVERT(VARCHAR(7),GETDATE(),120)
GROUP BY MONTH([time]),DAY([time])
--删除模拟数据
DROP TABLE TB
--结果
time SumCount
--------- -----------
12-01 121
12-10 112
12-14 422
--模拟数据表
create table [TB]([id] int,[time] datetime,[count] int)
--添加模拟数据
insert [TB]
select 1,'2012-12-01 02:00:00',42 union all
select 1,'2012-12-01 14:18:12',79 union all
select 1,'2012-12-10 07:15:42',112 union all
select 1,'2012-12-14 10:06:20',57 union all
select 1,'2012-12-14 11:54:10',124 union all
select 1,'2012-12-14 14:10:27',241
--声明空白数据
DECLARE @tbnull TABLE(id INT,[time] DATETIME,[count] INT)
--递增变量
DECLARE @day INT
SET @day=0
--当月天数
DECLARE @days INT
SELECT @days= day(dateadd(mm,1,getdate())-day(getdate()))
--循环插入空白数据
WHILE (@day<@days)
BEGIN
SET @day=@day+1
INSERT INTO @tbnull
( id, time, count )
VALUES ( 1,CONVERT(DATETIME,CONVERT(VARCHAR(8),GETDATE(),120)+RIGHT('00'+@day,2)),0)
END;
--合并数据
WITH data AS
(
SELECT * FROM TB
UNION ALL
SELECT * FROM @tbnull
)
--根据日前的月份和天数分组求和，
--条件为当前的月份转换成2012-12-14 00:00:00 的时间格式
--month()、day()函数返回值为整型，故转换为字符后拼接
--数据格式为2012-12-14 00:00:00可正常运行
SELECT CAST(MONTH([time]) AS VARCHAR(4))+'-'+RIGHT('00'+CAST(DAY([time]) AS VARCHAR(4)),2) AS [time],
SUM([count]) AS SumCount FROM data
WHERE CONVERT(VARCHAR(7),[time],120)=CONVERT(VARCHAR(7),GETDATE(),120)
GROUP BY MONTH([time]),DAY([time])
--删除模拟数据
DROP TABLE TB
--结果
time SumCount
--------- -----------
12-01 121
12-02 0
12-03 0
12-04 0
12-05 0
12-06 0
12-07 0
12-08 0
12-09 0
12-10 112
12-11 0
12-12 0
12-13 0
12-14 422
12-15 0
12-16 0
12-17 0
12-18 0
12-19 0
12-20 0
12-21 0
12-22 0
12-23 0
12-24 0
12-25 0
12-26 0
12-27 0
12-28 0
12-29 0
12-30 0
12-31 0
