我的学习笔记-Servlet简介及工作原理
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<%@ page language="java" import="java.util.*" pageEncoding="UTF-8"%><!DOCTYPE HTML PUBLIC "-//W3C//DTD HTML 4.01 Transitional//EN"><html> <head> </head> <body><form action="http://127.0.0.1:8080/JavaWebExercise/loginServlet" method="get">name:<input type="text" name="username"/><input type="submit" value ="submit"></form> </body></html>
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package com.foxmail.xxy668;import java.io.IOException;import javax.servlet.ServletException;import javax.servlet.http.HttpServlet;import javax.servlet.http.HttpServletRequest;import javax.servlet.http.HttpServletResponse;public class LoginServlet extends HttpServlet {@Overridepublic void doGet(HttpServletRequest request, HttpServletResponse response)throws ServletException, IOException {String username=request.getParameter("username");System.out.println("username="+username);response.setContentType("text/html;charset=UTF-8");response.getWriter().println(username+" login success");}@Overridepublic void doPost(HttpServletRequest req, HttpServletResponse resp)throws ServletException, IOException {doGet(req, resp);}}
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<?xml version="1.0" encoding="UTF-8"?><web-app version="2.5" xmlns="http://java.sun.com/xml/ns/javaee" xmlns:xsi="http://www.w3.org/2001/XMLSchema-instance" xsi:schemaLocation="http://java.sun.com/xml/ns/javaee http://java.sun.com/xml/ns/javaee/web-app_2_5.xsd"> <display-name></display-name> <welcome-file-list> <welcome-file>index.jsp</welcome-file> </welcome-file-list> <servlet> <servlet-name>MyServlet</servlet-name> <servlet-class>com.foxmail.xxy668.LoginServlet</servlet-class> </servlet> <servlet-mapping> <servlet-name>MyServlet</servlet-name> <url-pattern>/loginServlet</url-pattern> </servlet-mapping></web-app>?
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，，， 12 楼 万俟辉夜 2012-05-21 总结的很好。。。 13 楼 cd_huangbo 2012-05-21 只是一个简单的工作流程，貌似没涉及到原理讲解。