递归计算1/1+1/2+1/3+...+1/100
/* * 计算 1/1+1/2+1/3+...+1/100 的值 */#include<stdio.h>#include<stdlib.h> double getsum(int n){ if(n==1)return 1.0/1; else return 1.0/n+getsum(n-1);}int main(){ int n=100; double result=getsum(n); printf("result=%f\n",result);}?