javax.naming.NamingException-我的jbuilder中配置的tomcat连接池已经正
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我的测试页test.jsp,应该没什么问题
? <%@ page contentType="text/html; charset=GBK"%>
? <%@ page import="java.sql.*,javax.sql.DataSource,javax.naming.*"%>
? <html>
? <head><title>test.jsp</title></head>
? <body bgcolor="#ffffff">
? <h1>test Tomcat</h1>
? <%
? try
? {
? Context initCtx=new InitialContext();
? DataSource ds = (DataSource)initCtx.lookup("java:comp/env/jdbc/MySql_ResSys");
? Connection conn=ds.getConnection();
? out.println("data from database:<br>");
? Statement stmt=conn.createStatement();
? ResultSet rs =stmt.executeQuery("select id, name from testdata");
? while(rs.next())
? {
? out.println(rs.getInt("id"));
? out.println(rs.getString("name"));
? }
? rs.close();
? stmt.close();
? }
? catch(Exception e)
? {
? e.printStackTrace();
? }
? %>
? </body>
? </html>
? 当启动时出现以下错误：
? HttpConnector[8080] Starting background thread
? javax.naming.NamingException: Cannot create resource instance
? at org.apache.naming.factory.ResourceFactory.getObjectInstance(ResourceFactory.java:167)
? at javax.naming.spi.NamingManager.getObjectInstance(NamingManager.java:301)
? at org.apache.naming.NamingContext.lookup(NamingContext.java:834)
? at org.apache.naming.NamingContext.lookup(NamingContext.java:181)
? at org.apache.naming.NamingContext.lookup(NamingContext.java:822)
? at org.apache.naming.NamingContext.lookup(NamingContext.java:181)
? at org.apache.naming.NamingContext.lookup(NamingContext.java:822)
? at org.apache.naming.NamingContext.lookup(NamingContext.java:181)
? at org.apache.naming.NamingContext.lookup(NamingContext.java:822)
? at org.apache.naming.NamingContext.lookup(NamingContext.java:194)
? at org.apache.naming.SelectorContext.lookup(SelectorContext.java:183)
? at javax.naming.InitialContext.lookup(InitialContext.java:347)
? at org.apache.jsp.testjsp3$jsp._jspService(testjsp3$jsp.java:69)
? at org.apache.jasper.runtime.HttpJspBase.service(HttpJspBase.java:107)
? at javax.servlet.http.HttpServlet.service(HttpServlet.java:853)
? at org.apache.jasper.servlet.JspServlet$JspServletWrapper.service(JspServlet.java:201)???
????
??是何原因????
? javax.naming.NamingException: Cannot create resource instance??
------解决方法--------------------
应该是DataSource ds = (DataSource)initCtx.lookup("java:comp/env/jdbc/MySql_ResSys");
? 报出的异常，说明JNDI没有lookup到。
? 你的server8080.xml配置文件Context docBase="" path=""是否写对？不能有重复path等
------解决方法--------------------
你要使用res-ref-name
? <resource-ref>
? <description>DB Connection</description>
? <res-ref-name>jdbc/TestDB</res-ref-name>
? <res-type>javax.sql.DataSource</res-type>
? <res-auth>Container</res-auth>
? </resource-ref>
? lookup("java:comp/env/jdbc/TestDB");
