上机模拟试题（一）
上机模拟试题（一）
一、基本操作 （本大题共 4 小题，共 30 分）
?1.下列Application程序中，先创建一个Frame对象，然后设置Frame的大小（长、宽为200），背景为蓝色，Frame为可见，请将程序补充完整。
import? java.awt.*;
public? class? test_1_3_1{
public? static void main(String args[]){
Frame f=new Frame(“Hello World!”);
f.setSize__________;?????? //设置Frame的大小
f.setBackground(______.blue);? //设置Frame的背景
f.setVisible(_________);?????? //设置Frame为可见
}
}
?2. 下列Application程序中，指定ch为字符类型，指定bo为布尔类型，指定f为单精度类型，定义一些变量，执行相应输出，请将程序补充完整。
public? class? test_1_3_2{
public? static void main(String args[]){
_________f=1.876f;
_________bo=true;
_________ch;
System.out.println(“ch=”+ch);
System.out.println(“f=”+f);
System.out.println(“bo=”+bo);
??? }
}
3. 下列Application程序，要求在空格处输入运算符和变量，求出b的相反数，j的值输出0，k的值输出1，请将程序补充完整。
public? class? test_1_3_3{
public? static void main(String args[]){
int a=9;
int b=__________;
int i=0;
int j=___________;? //i=1,j=0
int k=__________;? //j=1,k=1
System.out.println(“a=”+a);
System.out.println(“b=”+b);
System.out.println(“i=”+i);
System.out.println(“j=”+j);
System.out.println(“k=”+k);
}
}
4. 下列Application程序输入一个正整数，将各位数字反转后输出，请根据注释，将程序补充完整。
public? class? test_1_3_4{
?public? static void main(String args[])throws IOException{
????? int? x;
//下面7行语句的作用是从键盘输入x的值
InputStreamReader? ir;
?? BufferedReader in;
?? ir=_________ InputStreamReader(System.in);
?? in=new BufferedReader(ir);
?? System.out.println(“Input x is:”);
?? String .s=in.readLine();
?? x=Integer.parseInt(s);
?//下面进行反转输出
?_____________
{
?System.out.print(x________10);//除以10取余数输出
?x/=10;
}while(x!=0);
?? System.out.print(“\n”);
}
}
二、简单应用 （本大题共 2 小题，共 30 分）
1.下面java程序实现对后序表达式的求值操作。请勿改动原有代码，在下划线处填入适当语句，将程序补充完整。
import? java.util.*;
import? java.io.*;
public? class? test_3_2_1{
public? static void main(String args[])throws Exception{
?? StackArray Operand=new StackArray();
?? String Expression=new String();
?? Int? Position=0;
?? Int? Operand1=0;
?? Int? Operand2=0;
?? System.out.println(“Please imput the postorder expression:”);
?? InputStreamReader? ir;
?? BufferedReader in;
? ir=new InputStreamReader(System.in);
? in=new BufferedReader(ir);
?? Expression=in.readLine();
?? While(true)??? {
??????? If(Operand.IsOperator(Expression.charAt(Position)))? {
???????????? Operand1= Operand.pop();
???????????? Operand2= Operand.pop();
Operand.Push(Operand.TwoResult(Expression.charAt(Position), Operand1, Operand2));
??? }
??? else
??? Operand.Push (Expression.charAt(Position)-48);
??? Position++;
??? If(Position>=Expression.length())
??? Break;
}
??? Evaluate=Operand.Pop();
??? System.out.print(“The expression[“+Expression+”]”);
?System.out.print(“result is”+Evaluate);
}
?}
? class StackArray{
int? MaxSize=20;
int? []Astack=new int[MaxSize];
int? Top=-1;
public void Push(int Value)? {
??? int? i;
??? if(Top>=MaxSize)
??????? System.out.print(“The stack is full”);
??? else???? {
??????? Top++;
????? ??Astack[Top]=value;
??? }
}
public int Pop()? {
???? int Temp;
???? int? i;
???? if(Top<0)? {
?????? System.out.println(“The stack is Empty!”);
?????? Return –1;
???? }
???? Temp=Astack[Top];
???? Return Temp;
? }
?public Boolean IsOperator(int Operator) ???{
????? if(Operator= =43||Operator= =45||Operator= =42||Operator= =47)
????????? return true;???? //+ ﹣ ＊ /
????? else
????????? reture false;
? }
public int Priority(int Operator)??? {
??? if(Operator= =43||Operator= =45)
??????? return? 1;???? //+ ﹣
??? else? if(Operator= =42|| Operator= =47)
?????? return? 2;???? //＊ /
?? else
?????? return? 0;
}
public int TwoResult(________)? {
??? switch(operator)????? {
??????? case 43:
???????????? return(operand1+ operand2);
??????? case 45:
???????????? return(operand1﹣operand2);
??????? case 42:
???????????? return(operand1*operand2);
??????? case 47:
????????? ??return(operand1/operand2);
??? }
??? return 0;
?? }
}
2.下面是一个字符界面的JAVA Application程序，它接受用户输入的一个浮点数，那它的整数部分和小数部分分别输出。请勿改动原有代码，在下划线处填入适当语句，将程序补充完整。
import? java.io.*;
public? class? test_3_2_2{
??????? public? static void main(String args[])? {
String s;
Double d;
Int i;
Boolean b=false;
do {
? try {
?? System.out.println(“请输入一个浮点数：”)；
?? BufferedReader br=new BufferedReader(new InputStreamReader(System.in));
?? s=br.readLine();
? i=s.indexOf(‘.’);
?? d=_________.parseDouble(s);
?? System.out.println(d+”整数部分为：”+_________);
? If(I= =-1)
?? System.out.println(d+”小数部分为：0.0”)；
? else
?? System.out.println(d+”小数部分为:”+Double.parseDouble(
((s.charAt(0)= =’﹣’)?” ﹣”:” ”)
+”0.”+s.substring(i+1,s.length())));
b=false;
????????????????? }
catch(NemberFormatException nfe)??? {
??? System.out.println(“输入浮点数格式有误。\n”);
??? B=true;
}
catch(IOException ioe)?? {
? b=false;
}
}while(b);
?????????? }
????????? }
?? 三、综合应用（本大题共 1 小题，共 40 分）
下面程序演示项目选择事件的处理。请改正其中的错误（有下划线的语句），使程序能输出正确的结果。
import? java.awt.event.*;
import? javax.swing.*;
import? java.awt. *;
public class test_3_3 extends JFrame implements ItemListener {
??? BorderLayout bord=new BorderLayout();
??? JTextField result=new JtextField27.;
??? JComboBox pick=new? JComboBox();
Public test_3_3() {
??? Super(“Select Item”);
??? pick.addItemListener(it);
??? pick.addItem(“Navigator”);
??? pick.addItem(“Internet Explorer”);
??? pick.addItem(“Opera”);
??? pick.setEditable(false);
??? result.setHorizontalAlignment(SwingConstants.CENTER);
??? result.setEditable(false);
??? Jpanel pane=new Jpanel();
??? Pane.add(result,”South”);
??? Pane.add(pick,”Center”);
??? SetContentPane(pane1);
? }
? public? static void main(String[] arguments)? {
??? Jframe frame=new SelectItem();
??? ExitWindow exit=new ExitWindow();
??? Frame.addWindowListener(exit);
??? Frame.pack();
??? Frame.setVisible(true);
?? }
? public void itemStatechanged(ItemEvent evt)? {
???? Object source=evt.getSource();
???? if(source= =pick) {
?????? Object newPick=evt.getItem();
?????? Result.setText(newPick.toString()+”is the selection.”);
??? }
??? repaint;
?}
}
