用与一个字符串长度相等的数量的线程，顺序输出N行相同的字符串
举例，输出N行的字符串"ABC"，就要用3个线程，每个线程分别负责输出一个字符，输出结果应该为N行的"ABC"
我的思路是：
public class TestThead {public static void main(String[] args) throws InterruptedException {String str = "ABCDEFGHIJKLMNOPQRSTUVWXYZ"; // 随便改什么字符串int runCount = 500; // 任意次数int strLength = str.length(); String[] strBuffer = new String[strLength * runCount]; // 字符串输出缓存Thread[] Ths = new Thread[strLength];for (int index = 0; index < strLength; index++) {Ths[index] = new Thread(new Runner(index, strBuffer, str, strLength, runCount));Ths[index].start();} //等待所有线程结束for (int index = 0; index < strLength; index++) {Ths[index].join();} //输出结果for (int i = 0; i < strBuffer.length; i++) {System.out.print(strBuffer[i]);if ((i + 1) % strLength == 0)System.out.println();}}}class Runner implements Runnable {String[] strBuffer;String str;int strLength;int index;int runCount;public Runner(int index, String[] strBuffer, String str, int strLength, int runCount) {this.index = index;this.runCount = runCount;this.strBuffer = strBuffer;this.str = str;this.strLength = strLength;}@Overridepublic void run() {for (int i = 0; i < runCount; i++) {strBuffer[strLength * i + index] = String.valueOf(str.charAt(index));}}}public class Tester {public static void main(String[] arg) {String str = "abc";Integer[] locker = new Integer[1];locker[0] = 0;for (int i = 0; i < str.length(); i++) {new Thread(new printStr(locker, str, 10)).start();}}}class printStr implements Runnable {Integer[] locker = null;String str = null;int COUNT;public printStr(Integer[] locker, String str, int cOUNT) {super();this.locker = locker;this.str = str;COUNT = cOUNT;}@Overridepublic void run() {synchronized (locker) {while (locker[0] < str.length() * COUNT) {System.out.print(str.charAt(locker[0]++ % str.length()));if (locker[0] % str.length() == 0)System.out.println();try {locker.notifyAll();locker.wait();} catch (InterruptedException e) {e.printStackTrace();}}locker.notifyAll();}}}