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单向列表倒悬

2012-11-23 
单向列表倒置单向列表倒置:算法示例:headendtmp 1----2----3----4----5endheadtmp 2----13----4----

单向列表倒置

单向列表倒置:


算法示例:


head  end   tmp
 1---->2---->3---->4---->5

end   head     tmp
 2---->1        3---->4---->5

head       end   tmp
 2---->1    3---->4---->5

end  head        tmp
 3---->2---->1    4---->5

head             end   tmp
 3---->2---->1    4---->5

end  head              tmp
 4---->3---->2---->1    5

head                   end   tmp
 4---->3---->2---->1    5    NULL

end  head
 5---->4---->3---->2---->1

示例代码:


#include <stdio.h>#include <stdlib.h>typedef struct LIST_NODE {struct LIST_NODE* next;int value;}LIST_NODE;LIST_NODE* list_inversion(LIST_NODE *head) {printf("in list_inversion\n");LIST_NODE *tmp, *end;end = head->next;tmp = end->next;head->next = NULL;while (NULL != tmp) {end->next = head;head = end;end = tmp;tmp = tmp->next;}end->next = head;return end;}int main() {LIST_NODE *head, *end;head = (LIST_NODE*)malloc(sizeof(LIST_NODE)*1);end = (LIST_NODE*)malloc(sizeof(LIST_NODE)*1);LIST_NODE* tmp = (LIST_NODE*)malloc(sizeof(LIST_NODE)*1);int len = 0, value = 0;printf("Input length of list :\n");scanf("%d", &len);tmp = head;for(int i= 0; i < len; i++) {LIST_NODE* tmp2 = (LIST_NODE*)malloc(sizeof(LIST_NODE)*1);printf("Input the current value : ");tmp->next = tmp2;if (i == len-1) {tmp->next = NULL;}scanf("%d", &value);tmp->value = value;tmp = tmp->next;}LIST_NODE *aList = list_inversion(head);printf("new list : \n");while (NULL != aList) {printf("%d\n", aList->value);aList= aList->next;}}

示例运行结果:

[root@localhost List]# ./listtest 
Input length of list :
5
Input the current value : 1
Input the current value : 2
Input the current value : 3
Input the current value : 4
Input the current value : 5
in list_inversion
new list : 
5
4
3
2
1

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