Quartz JDBCStore 和MethodInvokingJobDetailFactoryBean冲突的有关问题

2012-11-09

Quartz JDBCStore 和MethodInvokingJobDetailFactoryBean冲突的问题Note: JobDetails created via this F

Quartz JDBCStore 和MethodInvokingJobDetailFactoryBean冲突的问题
"Note: JobDetails created via this FactoryBean are not serializable and thus not suitable for persistent job stores. You need to implement your own Quartz Job as a thin wrapper for each case where you want a persistent job to delegate to a specific service method."

M类上有这么一句但是怎么做这种thin wrapper呢?

BO..




查API 确实有如此这段note 说jobDetails未序列化 需要对Quartz Job简单包装 

如何包装

从google 又获得信息如下


http://opensource.atlassian.com/projects/spring/browse/SPR-2462?page=all&decorator=printable


大概意思就是是否能把持久化的和临时的Jobs分开 还提到了setDurability(boolean durability) 

现在就看看这个方法 

不过思路有点混乱 需要被包装是哪个类？protected JobDetail retrieveJob(Connection conn, SchedulingContext ctxt,            String jobName, String groupName) throws JobPersistenceException {        try {            JobDetail job = getDelegate().selectJobDetail(conn, jobName,                    groupName, getClassLoadHelper());            if (job != null) {                String[] listeners = getDelegate().selectJobListeners(conn,                        jobName, groupName);                for (int i = 0; i < listeners.length; ++i) {                    job.addJobListener(listeners[i]);                }            }            return job;        } catch (ClassNotFoundException e) {            throw new JobPersistenceException(                    "Couldn't retrieve job because a required class was not found: "                            + e.getMessage(), e,                    SchedulerException.ERR_PERSISTENCE_JOB_DOES_NOT_EXIST);        } catch (IOException e) {            throw new JobPersistenceException(                    "Couldn't retrieve job because the BLOB couldn't be deserialized: "                            + e.getMessage(), e,                    SchedulerException.ERR_PERSISTENCE_JOB_DOES_NOT_EXIST);        } catch (SQLException e) {            throw new JobPersistenceException("Couldn't retrieve job: "                    + e.getMessage(), e);        }    }

18 楼 huangpengxiao 2006-11-30   重启之后又回到

Couldn't store trigger: It does not make sense to associate a non-volatile Trigger with a volatile Job!

郁闷了换换脑子搞点别的 19 楼 huangpengxiao 2006-11-30   顶有用过的没帮忙啊 20 楼 skyfly2424 2007-06-13   我也遇到了这个问题,刚解决了, 发现quartz.properties文件中使用了
org.quartz.jobStore.class = org.quartz.impl.jdbcjobstore.JobStoreTX
#org.quartz.jobStore.class = org.quartz.impl.jdbcjobstore.JobStoreCMT
#org.quartz.jobStore.driverDelegateClass = org.quartz.impl.jdbcjobstore.StdJDBCDelegate
org.quartz.jobStore.driverDelegateClass = org.quartz.impl.jdbcjobstore.MSSQLDelegate
#org.quartz.jobStore.driverDelegateClass = org.quartz.impl.jdbcjobstore.oracle.OracleDelegate
org.quartz.jobStore.useProperties = false
org.quartz.jobStore.dataSource = myDS
org.quartz.jobStore.tablePrefix = QRTZ_
org.quartz.jobStore.isClustered = false
这些配置,他会把JOB保存到数据库中, 所以要序列化 ,注释掉就OK了 21 楼 huangpengxiao 2007-06-13   skyfly2424 写道我也遇到了这个问题,刚解决了, 发现quartz.properties文件中使用了
org.quartz.jobStore.class = org.quartz.impl.jdbcjobstore.JobStoreTX
#org.quartz.jobStore.class = org.quartz.impl.jdbcjobstore.JobStoreCMT
#org.quartz.jobStore.driverDelegateClass = org.quartz.impl.jdbcjobstore.StdJDBCDelegate
org.quartz.jobStore.driverDelegateClass = org.quartz.impl.jdbcjobstore.MSSQLDelegate
#org.quartz.jobStore.driverDelegateClass = org.quartz.impl.jdbcjobstore.oracle.OracleDelegate
org.quartz.jobStore.useProperties = false
org.quartz.jobStore.dataSource = myDS
org.quartz.jobStore.tablePrefix = QRTZ_
org.quartz.jobStore.isClustered = false
这些配置,他会把JOB保存到数据库中, 所以要序列化 ,注释掉就OK了

谢谢楼上，这是半年之前的问题了，其实当时我就是要把job保存在数据库中因为如果不这样，一旦服务器宕机，我的JOB就销声匿迹了. 22 楼 huangpengxiao 2007-06-23   其实这个问题就是如何让MehiodInvokingJobDetailFactoryBean这个类关联的那个Job持久化.

如果你给这个类配置了DataSource 你会发现这个是个错误的选择

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Quartz JDBCStore 和MethodInvokingJobDetailFactoryBean冲突的有关问题