Java判断IP是不是在指定范围

Java判断IP是否在指定范围
2009-07-22 11:12

1. public class ipTest {?? ????/**
2. ????? * 判断IP是否在指定范围； ????? */??
3. ????boolean i;?? ????public static boolean ipIsValid(String ipSection, String ip) {??
4. ????????if (ipSection == null)?? ????????????throw new NullPointerException("IP段不能为空！");??
5. ????????if (ip == null)?? ????????????throw new NullPointerException("IP不能为空！");??
6. ???????? ipSection = ipSection.trim();?? ???????? ip = ip.trim();??
7. ????????final String REGX_IP = "((25[0-5]|2[0-4]\\d|1\\d{2}|[1-9]\\d|\\d)\\.){3}(25[0-5]|2[0-4]\\d|1\\d{2}|[1-9]\\d|\\d)";?? ????????final String REGX_IPB = REGX_IP + "\\-" + REGX_IP;??
8. ????????if (!ipSection.matches(REGX_IPB) || !ip.matches(REGX_IP))?? ????????????return false;??
9. ????????int idx = ipSection.indexOf('-');?? ???????? String[] sips = ipSection.substring(0, idx).split("\\.");??
10. ???????? String[] sipe = ipSection.substring(idx + 1).split("\\.");?? ???????? String[] sipt = ip.split("\\.");??
11. ????????long ips = 0L, ipe = 0L, ipt = 0L;?? ????????for (int i = 0; i < 4; ++i) {??
12. ???????????? ips = ips << 8 | Integer.parseInt(sips[i]);?? ???????????? ipe = ipe << 8 | Integer.parseInt(sipe[i]);??
13. ???????????? ipt = ipt << 8 | Integer.parseInt(sipt[i]);?? ???????? }??
14. ????????if (ips > ipe) {?? ????????????long t = ips;??
15. ???????????? ips = ipe;?? ???????????? ipe = t;??
16. ???????? }?? ????????return ips <= ipt && ipt <= ipe;??
17. ???? }?? ????public static void main(String[] args) {??
18. ????????if (ipIsValid("192.168.1.1-192.168.1.10", "192.168.3.54")) {?? ???????????? System.out.println("ip属于该网段");??
19. ???????? } else?? ???????????? System.out.println("ip不属于该网段");??
20. ???? }?? }