菜鸟Struts2 无法获取页面的值 求答案

初学者Struts2 无法获取页面的值 求答案
文件如下
LoginActionForm.java

Java code

import com.opensymphony.xwork2.ActionSupport;import com.lee.user.user.*;public class LoginActionForm extends ActionSupport{    User us = new User();    public String execute(){        System.out.println("username:"+us.getUserName());        System.out.println("password:"+us.getPassWord());        return SUCCESS;    }}

User.java

Java code

public class User {    private String UserName;    private String PassWord;            /**     * @return the userName     */    public String getUserName() {        return UserName;    }    /**     * @param userName the userName to set     */    public void setUserName(String userName) {        UserName = userName;    }    /**     * @return the passWord     */    public String getPassWord() {        return PassWord;    }    /**     * @param passWord the passWord to set     */    public void setPassWord(String passWord) {        PassWord = passWord;    }}

login.jsp

Java code

<s:form action="login" method="post">   <s:textfield name="UserName" label="用户名"></s:textfield>   <s:password name="PassWord" label="密码"></s:password>   <s:submit label="登陆" value="登陆"></s:submit>  </s:form>

struts.xml

Java code

<package name="default" namespace="/" extends="struts-default">     <action name="loginindex">         <result>login.jsp</result>     </action>     <action name="login" class="com.lee.user.form.LoginActionForm">         <result name="success">wellcom.jsp</result>         <result name="error">error.jsp</result>     </action>          <action name="goback">         <result name="success">login.jsp</result>     </action>          </package>

web.xml

Java code

 <welcome-file-list>    <welcome-file>index.jsp</welcome-file>  </welcome-file-list>  <filter>      <filter-name>struts2</filter-name>      <filter-class>          org.apache.struts2.dispatcher.ng.filter.StrutsPrepareAndExecuteFilter      </filter-class>  </filter>  <filter-mapping>      <filter-name>struts2</filter-name>      <url-pattern>/*</url-pattern>  </filter-mapping>

为什么在action中定义页面属性就能获取到值，但是像这样分开后就拿不到值了呢？求解.

[解决办法]
public class LoginActionForm extends ActionSupport{
User us = new User();//不需要new User 为us生成getter和setter方法
public String execute(){
System.out.println("username:"+us.getUserName());
System.out.println("password:"+us.getPassWord());
return SUCCESS;
}

}

<s:form action="login" method="post">
<s:textfield name="UserName" label="用户名"></s:textfield>// name=us.UserName
<s:password name="PassWord" label="密码"></s:password> // name=us.PassWord

<s:submit label="登陆" value="登陆"></s:submit>
</s:form>

[解决办法]

Java code

private User us;封装jsp中 <s:textfield name="us.UserName" label="用户名"></s:textfield>
[解决办法]
Java code
public class LoginActionForm extends ActionSupport{  User us = new User();  public String execute(){  System.out.println("username:"+us.getUserName());  System.out.println("password:"+us.getPassWord());  return SUCCESS;  }以上写也可以 你继承user类就ok了不过不能用execute（）方法了 而行写项目都不用execute方法的配置struts2 method=“方法名”<action name="login" class="com.lee.user.form.LoginActionForm" method="方法名">
[解决办法]
  你是用Spring依赖注入的吗？  在LoginActionForm 类中你就不需要再取NEW 不然的话它每次都是NEW一个新的，所以为空，
[解决办法]
页面上的
<s:textfield name="UserName" label="用户名"></s:textfield>
  <s:password name="PassWord" label="密码"></s:password>
name属性值最好小写。
[解决办法]
探讨


public class LoginActionForm extends ActionSupport{
    User us = new User();//不需要new User 为us生成getter和setter方法
    public String execute(){
        System.out.println("username:"+us.getUserName()……

[解决办法]
探讨

Java code

private User us;封装
jsp中
 <s:textfield name="us.UserName" label="用户名"></s:textfield>
 

 

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