hdu1849 Rabbit and Grass 距离转为NIM 水题

#include<iostream>#include<cstdlib>#include<stdio.h>using namespace std;int main(){    int n,num;    while(scanf("%d",&n)&&n)    {        int ans=0;        for(int i=0;i<n;i++)        {            scanf("%d",&num);            ans^=num;        }        if(ans) puts("Rabbit Win!");        else puts("Grass Win!");    }}/*23 533 5 60Rabbit Win!Grass Win!*/

Rabbit and GrassTime Limit: 1000/1000 MS (Java/Others)    Memory Limit: 32768/32768 K (Java/Others)
Total Submission(s): 1088    Accepted Submission(s): 816


Problem Description

大家知道，虽然偶尔不够浪漫，但是Rabbit和Grass都是冰雪聪明的女生，如果每次都是Rabbit先走棋，请输出最后的结果。InputOutputSample InputSample OutputAuthorSourceRecommendlcy