金额转换
小弟刚学Java,请教大哥大姐们一个问题:阿拉伯数字转换成中国传统的形式如:(¥1011)—>(一千零佰一拾一元整)输出。提示:输入时只输入数字,输出中国传统形式的字符串。
[解决办法]
zi ji yan jiu ba
public class Reader { private String strNum; private String strNumChFormat; private String strNumTemp; private int intNumLen; private String strBegin; public Reader(String strNum) { this.strNum = strNum; } public boolean check(String strNum) { boolean valid = false; if (strNum.substring(0,1).equals("0")){ this.strNum = strNum.substring(1); } try { new Double(strNum); valid = true; } catch (NumberFormatException ex) { System.out.println("Bad number format!"); } return valid; } public void init() { strNumChFormat = ""; intNumLen = strNum.length(); strNumTemp = strNum; strNumTemp = strNumTemp.replace('1', '一'); strNumTemp = strNumTemp.replace('2', '二'); strNumTemp = strNumTemp.replace('3', '三'); strNumTemp = strNumTemp.replace('4', '四'); strNumTemp = strNumTemp.replace('5', '五'); strNumTemp = strNumTemp.replace('6', '六'); strNumTemp = strNumTemp.replace('7', '七'); strNumTemp = strNumTemp.replace('8', '八'); strNumTemp = strNumTemp.replace('9', '九'); strNumTemp = strNumTemp.replace('0', '零'); strNumTemp = strNumTemp.replace('.', '点'); strBegin = strNumTemp.substring(0, 1); } public String readNum() { if (check(strNum)) { init(); try { for (int i = 1, j = 1, k = 1; i < intNumLen; i++) { if (strNumTemp.charAt(intNumLen - 1) == '零' && i == 1) { strNumChFormat = "位"; } else if (strNumTemp.charAt(intNumLen - i) == '零' && j == 1) { strNumChFormat = "位" + strNumChFormat; } else if (strNumTemp.charAt(intNumLen - i) == '点') { j = 1; k = 1; strNumChFormat = strNumTemp.charAt(intNumLen - i) + strNumChFormat; continue; } else { strNumChFormat = strNumTemp.charAt(intNumLen - i) + strNumChFormat; } if (strNumTemp.charAt(intNumLen - i - 1) != '位' && strNumTemp.charAt(intNumLen - i - 1) != '零') { if (j == 1 && i < intNumLen) { strNumChFormat = '拾' + strNumChFormat; } else if (j == 2 && i < intNumLen) { strNumChFormat = '百' + strNumChFormat; } else if (j == 3 && i < intNumLen) { strNumChFormat = '千' + strNumChFormat; } } if (j == 4 && i < intNumLen) { j = 0; } if (k == 4 && i < intNumLen) { strNumChFormat = '万' + strNumChFormat; } else if (k == 8 && i < intNumLen) { k = 0; strNumChFormat = '亿' + strNumChFormat; } j++; k++; } while (strNumChFormat.indexOf("位") != -1) { strNumChFormat = strNumChFormat.replaceAll("位", " "); } if (strNumChFormat.substring(0, 2) == "一拾") { strNumChFormat = strNumChFormat.substring(1, strNumChFormat.length()); } if (strNumChFormat.indexOf("点") >= 0) { String rebegin = strNumChFormat.substring(0, strNumChFormat.indexOf("点")); String relast = strNumChFormat.substring(strNumChFormat.indexOf("点"), strNumChFormat.length()); for (int i = 1; i <= relast.length(); i++) { relast = relast.replaceAll("拾", ""); relast = relast.replaceAll("百", ""); relast = relast.replaceAll("千", ""); relast = relast.replaceAll("万", ""); relast = relast.replaceAll("亿", ""); } strNumChFormat = rebegin + relast; } } catch (ArrayIndexOutOfBoundsException ex) { ex.printStackTrace(); } catch (Exception ex) { ex.printStackTrace(); } int off = strNumChFormat.indexOf("点"); strNumChFormat = strBegin + strNumChFormat.substring(0); } else { strNumChFormat = ""; } return strNumChFormat; } public static void main(String args[]) { try { String number = args[0].toString(); System.out.println("The number is: " + number); Reader reader = new Reader(number); System.out.println("Output String: " + reader.readNum()); } catch (Exception ex) { System.out.println("Please input like that: javac Reader <number>"); } }}
[解决办法]
/** * 念10万以内的任意数字。例如534念作伍佰叁十肆, * 203念作贰佰零叁。7003念作柒千零叁。 */public class Exec5 { public static void main(String[] args) { int n = 10; //拆分数字 /* * 个位数字放在数组的末尾, * 十位数字放在倒数第二个,依次类推 */ int[] number = new int[10]; int num = 0; //拆出的数字个数 int len = number.length; int temp = n; while(temp > 0){ //存储拆分出的数字 number[len - 1 - num] = temp % 10; num++; temp /= 10; //去掉个位数字 } //转换为大写 char[] upper = {'零','壹', '贰','叁','肆','伍','陆','柒','捌','玖' }; char[] right = {' ','拾','佰','千','万'}; String s = ""; boolean b = false; for(int i = len - num;i < len;i++){ if(number[i] == 0){ b = true; }else{ if(b){ s = s + "零"; b = false; } s = s + upper[number[i]] + right[len - i - 1]; } } System.out.println(s); }}
[解决办法]
package NumToRMB;
public class Class1 {
public static String ConvertNumberToChinese(String x, String[] Nums, String[] Digits, String[] Units)
{
String S = ""; //返回值
int p = 0; //字符位置指针
int m = x.length() % 4; //取模
// 四位一组得到组数
int k = (m > 0 ? x.length() / 4 + 1 : x.length() / 4);
// 外层循环在所有组中循环
// 从左到右 高位到低位 四位一组 逐组处理
// 每组最后加上一个单位: "[万亿]","[亿]","[万]"
for (int i = k; i > 0; i--)
{
int L = 4;
if (i == k && m != 0)
{
L = m;
}
// 得到一组四位数 最高位组有可能不足四位
String s = x.substring(p, p + L);
int l = s.length();
// 内层循环在该组中的每一位数上循环 从左到右 高位到低位
for (int j = 0; j < l; j++)
{
//处理改组中的每一位数加上所在位: "仟","佰","拾",""(个)
int n = java.lang.Integer.parseInt(s.substring(j, j+1));
if (n == 0)
{
if ((j < l - 1)
&& (java.lang.Integer.parseInt(s.substring(j + 1, j + 1+ 1)) > 0) //后一位(右低)
&& !S.endsWith(Nums[n]))
{
S += Nums[n];
}
}
else
{
//处理 1013 一千零"十三", 1113 一千一百"一十三"
if (!(n == 1 && (S.endsWith(Nums[0]) | S.length() == 0) && j == l - 2))
{
S += Nums[n];
}
S += Digits[l - j - 1];
}
}
p += L;
// 每组最后加上一个单位: [万],[亿] 等
if (i < k) //不是最高位的一组
{
if (java.lang.Integer.parseInt(s) != 0)
{
//如果所有 4 位不全是 0 则加上单位 [万],[亿] 等
S += Units[i - 1];
}
}
else
{
//处理最高位的一组,最后必须加上单位
S += Units[i - 1];
}
}
return S;
}
// 测试程序
public static void main(String[] args) throws Exception
{
//数字 数组
String[] Nums = new String[] {"零", "壹", "贰", "叁", "肆", "伍", "陆", "柒", "捌", "玖"};
//位 数组
String[] Digits = new String[] {"", "拾", "佰", "仟"};
//单位 数组
String[] Units = new String[] {"", "[万]", "[亿]", "[万亿]"};
System.out.println(ConvertNumberToChinese("111112100113", Nums, Digits, Units));
System.out.println(ConvertNumberToChinese("1100000000", Nums, Digits, Units));
System.out.println(ConvertNumberToChinese("1000000000", Nums, Digits, Units));
System.out.println(ConvertNumberToChinese("40000000013", Nums, Digits, Units));
System.out.println(ConvertNumberToChinese("40000000001", Nums, Digits, Units));
System.out.println(ConvertNumberToChinese("400000010000", Nums, Digits, Units));
System.out.println(ConvertNumberToChinese("40101031013", Nums, Digits, Units));
System.out.println(ConvertNumberToChinese("40101031113", Nums, Digits, Units));
System.out.println(ConvertNumberToChinese("101140101031013", Nums, Digits, Units));
System.out.println(ConvertNumberToChinese("100000001000013", Nums, Digits, Units));
System.out.println(ConvertNumberToChinese("100000001000113", Nums, Digits, Units));
System.out.println(ConvertNumberToChinese("100011003", Nums, Digits, Units));
System.out.println(ConvertNumberToChinese("10010103", Nums, Digits, Units));
System.out.println(ConvertNumberToChinese("10110013", Nums, Digits, Units));
System.out.println(ConvertNumberToChinese("130000", Nums, Digits, Units));
//System.in.read();
}
}