SQL求百分比
数据如下
pid pname 1 AA 2 AA 3 BB 4 AA 5 BB
Pname perAA 60%BB 40%
SELECT PName, CAST(COUNT(1)*1.0/(select count(1) from tb) AS DEC(18,0))AS TFROM TBGROUP BY PNAME
[解决办法]
--测试数据create table #a ( pid int ,pname varchar(10))insert into #a select 1,'aa' union allselect 2,'aa' union allselect 3,'bb' union allselect 4,'aa' union allselect 5 ,'bb' --表达式declare @sql varchar(800)set @sql ='select pname ,convert(varchar(10),cast(count(1)*100/(select count(1)from #a) as decimal(18,2)))+''%'' as per from #a group by pname'print @sqlexec(@sql)--结果:pname per---------- -----------aa 60.00%bb 40.00%