oracle队列转换总结(转载)

2012-09-02

oracle行列转换总结(转载)oracle行列转换总结最近论坛很多人提的问题都与行列转换有关系，所以我对行列转换

oracle行列转换总结(转载)

oracle行列转换总结

最近论坛很多人提的问题都与行列转换有关系，所以我对行列转换的相关知识做了一个总结，
希望对大家有所帮助，同时有何错疏，恳请大家指出，
我也是在写作过程中学习，算是一起和大家学习吧。

行列转换包括以下六种情况：
*列转行
*行转列
*多列转换成字符串
*多行转换成字符串
*字符串转换成多列
*字符串转换成多行

下面分别进行举例介绍。

首先声明一点，有些例子需要如下10g及以后才有的知识：
a。掌握model子句，
b。正则表达式
c。加强的层次查询

讨论的适用范围只包括8i,9i,10g及以后版本。begin：

1、列转行
CREATE TABLE t_col_row(
ID INT,
c1 VARCHAR2(10),
c2 VARCHAR2(10),
c3 VARCHAR2(10));

INSERT INTO t_col_row VALUES (1, 'v11', 'v21', 'v31');
INSERT INTO t_col_row VALUES (2, 'v12', 'v22', NULL);
INSERT INTO t_col_row VALUES (3, 'v13', NULL, 'v33');
INSERT INTO t_col_row VALUES (4, NULL, 'v24', 'v34');
INSERT INTO t_col_row VALUES (5, 'v15', NULL, NULL);
INSERT INTO t_col_row VALUES (6, NULL, NULL, 'v35');
INSERT INTO t_col_row VALUES (7, NULL, NULL, NULL);
COMMIT;

SELECT * FROM t_col_row;

1)UNION ALL
适用范围：8i,9i,10g及以后版本
SELECT id, 'c1' cn, c1 cv
? FROM t_col_row
UNION ALL
SELECT id, 'c2' cn, c2 cv
? FROM t_col_row
UNION ALL
SELECT id, 'c3' cn, c3 cv FROM t_col_row;

若空行不需要转换，只需加一个where条件，
WHERE COLUMN IS NOT NULL 即可。

2)MODEL
适用范围：10g及以后
SELECT id, cn, cv FROM t_col_row
MODEL
RETURN UPDATED ROWS
PARTITION BY (ID)
DIMENSION BY (0 AS n)
MEASURES ('xx' AS cn,'yyy' AS cv,c1,c2,c3)
RULES UPSERT ALL
(
? cn[1] = 'c1',
? cn[2] = 'c2',
? cn[3] = 'c3',
? cv[1] = c1[0],
? cv[2] = c2[0],
? cv[3] = c3[0]
? )
ORDER BY ID,cn;

3)collection
适用范围：8i,9i,10g及以后版本
要创建一个对象和一个集合：
CREATE TYPE cv_pair AS OBJECT(cn VARCHAR2(10),cv VARCHAR2(10));

CREATE TYPE cv_varr AS VARRAY(8) OF cv_pair;

SELECT id, t.cn AS cn, t.cv AS cv
? FROM t_col_row,
?????? TABLE(cv_varr(cv_pair('c1', t_col_row.c1),
???????????????????? cv_pair('c2', t_col_row.c2),
???????????????????? cv_pair('c3', t_col_row.c3))) t
ORDER BY 1, 2;

[ 本帖最后由 zhangfengh 于 2008-7-4 21:47 编辑 ]

?
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?#2使用道具? 发表于 2008-7-4 21:14??
接上

2、行转列

CREATE TABLE t_row_col AS
SELECT id, 'c1' cn, c1 cv
? FROM t_col_row
UNION ALL
SELECT id, 'c2' cn, c2 cv
? FROM t_col_row
UNION ALL
SELECT id, 'c3' cn, c3 cv FROM t_col_row;

SELECT * FROM t_row_col ORDER BY 1,2;

1)AGGREGATE FUNCTION
适用范围：8i,9i,10g及以后版本
SELECT id,
?????? MAX(decode(cn, 'c1', cv, NULL)) AS c1,
?????? MAX(decode(cn, 'c2', cv, NULL)) AS c2,
?????? MAX(decode(cn, 'c3', cv, NULL)) AS c3
? FROM t_row_col
GROUP BY id
ORDER BY 1;

MAX聚集函数也可以用sum、min、avg等其他聚集函数替代。

被指定的转置列只能有一列，但固定的列可以有多列，请看下面的例子：

SELECT mgr, deptno, empno, ename FROM emp ORDER BY 1, 2;

SELECT mgr,
?????? deptno,
?????? MAX(decode(empno, '7788', ename, NULL)) "7788",
?????? MAX(decode(empno, '7902', ename, NULL)) "7902",
?????? MAX(decode(empno, '7844', ename, NULL)) "7844",
?????? MAX(decode(empno, '7521', ename, NULL)) "7521",
?????? MAX(decode(empno, '7900', ename, NULL)) "7900",
?????? MAX(decode(empno, '7499', ename, NULL)) "7499",
?????? MAX(decode(empno, '7654', ename, NULL)) "7654"
? FROM emp
WHERE mgr IN (7566, 7698)
?? AND deptno IN (20, 30)
GROUP BY mgr, deptno
ORDER BY 1, 2;

这里转置列为empno，固定列为mgr，deptno。

还有一种行转列的方式，就是相同组中的行值变为单个列值，但转置的行值不变为列名：

ID??????? CN_1??????? CV_1??????? CN_2??????? CV_2??????? CN_3??????? CV_3
1??????????????? c1??????????????? v11??????????????? c2??????????????? v21??????????????? c3??????????????? v31
2??????????????? c1??????????????? v12??????????????? c2??????????????? v22??????????????? c3???????????????
3??????????????? c1??????????????? v13??????????????? c2??????????????????????????????????????? c3??????????????? v33
4??????????????? c1??????????????????????????????????????? c2??????????????? v24??????????????? c3??????????????? v34
5??????????????? c1??????????????? v15??????????????? c2??????????????????????????????????????? c3???????????????
6??????????????? c1??????????????????????????????????????? c2??????????????????????????????????????? c3??????????????? v35
7??????????????? c1??????????????????????????????????????? c2??????????????????????????????????????? c3

这种情况可以用分析函数实现：

SELECT id,
?????? MAX(decode(rn, 1, cn, NULL)) cn_1,
?????? MAX(decode(rn, 1, cv, NULL)) cv_1,
?????? MAX(decode(rn, 2, cn, NULL)) cn_2,
?????? MAX(decode(rn, 2, cv, NULL)) cv_2,
?????? MAX(decode(rn, 3, cn, NULL)) cn_3,
?????? MAX(decode(rn, 3, cv, NULL)) cv_3
? FROM (SELECT id,
?????????????? cn,
?????????????? cv,
?????????????? row_number() over(PARTITION BY id ORDER BY cn, cv) rn
????????? FROM t_row_col)
GROUP BY ID;

2)PL/SQL
适用范围：8i,9i,10g及以后版本
这种对于行值不固定的情况可以使用。
下面是我写的一个包，包中
p_rows_column_real用于前述的第一种不限定列的转换；
p_rows_column用于前述的第二种不限定列的转换。

CREATE OR REPLACE PACKAGE pkg_dynamic_rows_column AS
? TYPE refc IS REF CURSOR;

? PROCEDURE p_print_sql(p_txt VARCHAR2);

? FUNCTION f_split_str(p_str VARCHAR2, p_division VARCHAR2, p_seq INT)
??? RETURN VARCHAR2;

? PROCEDURE p_print_sql(p_txt VARCHAR2) IS
??? v_len INT;
? BEGIN
??? v_len := length(p_txt);
??? FOR i IN 1 .. v_len / 250 + 1 LOOP
????? dbms_output.put_line(substrb(p_txt, (i - 1) * 250 + 1, 250));
??? END LOOP;
? END;

? FUNCTION f_split_str(p_str VARCHAR2, p_division VARCHAR2, p_seq INT)
??? RETURN VARCHAR2 IS
??? v_first INT;
??? v_last? INT;
? BEGIN
??? IF p_seq < 1 THEN
????? RETURN NULL;
??? END IF;
??? IF p_seq = 1 THEN
????? IF instr(p_str, p_division, 1, p_seq) = 0 THEN
??????? RETURN p_str;
????? ELSE
??????? RETURN substr(p_str, 1, instr(p_str, p_division, 1) - 1);
????? END IF;
??? ELSE
????? v_first := instr(p_str, p_division, 1, p_seq - 1);
????? v_last? := instr(p_str, p_division, 1, p_seq);
????? IF (v_last = 0) THEN
??????? IF (v_first > 0) THEN
????????? RETURN substr(p_str, v_first + 1);
??????? ELSE
????????? RETURN NULL;
??????? END IF;
????? ELSE
??????? RETURN substr(p_str, v_first + 1, v_last - v_first - 1);
????? END IF;
??? END IF;
? END f_split_str;

? PROCEDURE p_rows_column(p_table????? IN VARCHAR2,
????????????????????????? p_keep_cols? IN VARCHAR2,
????????????????????????? p_pivot_cols IN VARCHAR2,
????????????????????????? p_where????? IN VARCHAR2 DEFAULT NULL,
????????????????????????? p_refc?????? IN OUT refc) IS
??? v_sql VARCHAR2(4000);
??? TYPE v_keep_ind_by IS TABLE OF VARCHAR2(4000) INDEX BY BINARY_INTEGER;
??? v_keep v_keep_ind_by;
?
??? TYPE v_pivot_ind_by IS TABLE OF VARCHAR2(4000) INDEX BY BINARY_INTEGER;
??? v_pivot v_pivot_ind_by;
?
??? v_keep_cnt?? INT;
??? v_pivot_cnt? INT;
??? v_max_cols?? INT;
??? v_partition? VARCHAR2(4000);
??? v_partition1 VARCHAR2(4000);
??? v_partition2 VARCHAR2(4000);
? BEGIN
??? v_keep_cnt? := length(p_keep_cols) - length(REPLACE(p_keep_cols, ',')) + 1;
??? v_pivot_cnt := length(p_pivot_cols) -
?????????????????? length(REPLACE(p_pivot_cols, ',')) + 1;
??? FOR i IN 1 .. v_keep_cnt LOOP
????? v_keep(i) := f_split_str(p_keep_cols, ',', i);
??? END LOOP;
??? FOR j IN 1 .. v_pivot_cnt LOOP
????? v_pivot(j) := f_split_str(p_pivot_cols, ',', j);
??? END LOOP;
??? v_sql := 'select max(count(*)) from ' || p_table || ' group by ';
??? FOR i IN 1 .. v_keep.LAST LOOP
????? v_sql := v_sql || v_keep(i) || ',';
??? END LOOP;
??? v_sql := rtrim(v_sql, ',');
??? EXECUTE IMMEDIATE v_sql
????? INTO v_max_cols;
??? v_partition := 'select ';
??? FOR x IN 1 .. v_keep.COUNT LOOP
????? v_partition1 := v_partition1 || v_keep(x) || ',';
??? END LOOP;
??? FOR y IN 1 .. v_pivot.COUNT LOOP
????? v_partition2 := v_partition2 || v_pivot(y) || ',';
??? END LOOP;
??? v_partition1 := rtrim(v_partition1, ',');
??? v_partition2 := rtrim(v_partition2, ',');
??? v_partition? := v_partition || v_partition1 || ',' || v_partition2 ||
??????????????????? ', row_number() over (partition by ' || v_partition1 ||
??????????????????? ' order by ' || v_partition2 || ') rn from ' || p_table;
??? v_partition? := rtrim(v_partition, ',');
??? v_sql??????? := 'select ';
??? FOR i IN 1 .. v_keep.COUNT LOOP
????? v_sql := v_sql || v_keep(i) || ',';
??? END LOOP;
??? FOR i IN 1 .. v_max_cols LOOP
????? FOR j IN 1 .. v_pivot.COUNT LOOP
??????? v_sql := v_sql || ' max(decode(rn,' || i || ',' || v_pivot(j) ||
???????????????? ',null))' || v_pivot(j) || '_' || i || ',';
????? END LOOP;
??? END LOOP;
??? IF p_where IS NOT NULL THEN
????? v_sql := rtrim(v_sql, ',') || ' from (' || v_partition || ' ' ||
?????????????? p_where || ') group by ';
??? ELSE
????? v_sql := rtrim(v_sql, ',') || ' from (' || v_partition ||
?????????????? ') group by ';
??? END IF;
??? FOR i IN 1 .. v_keep.COUNT LOOP
????? v_sql := v_sql || v_keep(i) || ',';
??? END LOOP;
??? v_sql := rtrim(v_sql, ',');
??? p_print_sql(v_sql);
??? OPEN p_refc FOR v_sql;
? EXCEPTION
??? WHEN OTHERS THEN
????? OPEN p_refc FOR
??????? SELECT 'x' FROM dual WHERE 0 = 1;
? END;

? PROCEDURE p_rows_column_real(p_table???? IN VARCHAR2,
?????????????????????????????? p_keep_cols IN VARCHAR2,
?????????????????????????????? p_pivot_col IN VARCHAR2,
?????????????????????????????? p_pivot_val IN VARCHAR2,
?????????????????????????????? p_where???? IN VARCHAR2 DEFAULT NULL,
?????????????????????????????? p_refc????? IN OUT refc) IS
??? v_sql VARCHAR2(4000);
??? TYPE v_keep_ind_by IS TABLE OF VARCHAR2(4000) INDEX BY BINARY_INTEGER;
??? v_keep v_keep_ind_by;
??? TYPE v_pivot_ind_by IS TABLE OF VARCHAR2(4000) INDEX BY BINARY_INTEGER;
??? v_pivot??? v_pivot_ind_by;
??? v_keep_cnt INT;
??? v_group_by VARCHAR2(2000);
? BEGIN
??? v_keep_cnt := length(p_keep_cols) - length(REPLACE(p_keep_cols, ',')) + 1;
??? FOR i IN 1 .. v_keep_cnt LOOP
????? v_keep(i) := f_split_str(p_keep_cols, ',', i);
??? END LOOP;
??? v_sql := 'select ' || 'cast(' || p_pivot_col ||
???????????? ' as varchar2(200)) as ' || p_pivot_col || ' from ' || p_table ||
???????????? ' group by ' || p_pivot_col;
??? EXECUTE IMMEDIATE v_sql BULK COLLECT
????? INTO v_pivot;
??? FOR i IN 1 .. v_keep.COUNT LOOP
????? v_group_by := v_group_by || v_keep(i) || ',';
??? END LOOP;
??? v_group_by := rtrim(v_group_by, ',');
??? v_sql????? := 'select ' || v_group_by || ',';
?
??? FOR x IN 1 .. v_pivot.COUNT LOOP
????? v_sql := v_sql || ' max(decode(' || p_pivot_col || ',' || chr(39) ||
?????????????? v_pivot(x) || chr(39) || ',' || p_pivot_val ||
?????????????? ',null)) as "' || v_pivot(x) || '",';
??? END LOOP;
??? v_sql := rtrim(v_sql, ',');
??? IF p_where IS NOT NULL THEN
????? v_sql := v_sql || ' from ' || p_table || p_where || ' group by ' ||
?????????????? v_group_by;
??? ELSE
????? v_sql := v_sql || ' from ' || p_table || ' group by ' || v_group_by;
??? END IF;
??? p_print_sql(v_sql);
??? OPEN p_refc FOR v_sql;
? EXCEPTION
??? WHEN OTHERS THEN
????? OPEN p_refc FOR
??????? SELECT 'x' FROM dual WHERE 0 = 1;
? END;

END;
/

[ 本帖最后由 zhangfengh 于 2008-7-4 21:49 编辑 ]

?
__________________
我不在江湖，但江湖中有我的传说；
我身在江湖，江湖里却没有我的传说。
只看该作者?????
?
?caizhuoyi
Oracle Stranger

精华贴数 3
个人空间 0
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?????
??????

?#3使用道具? 发表于 2008-7-4 21:15??
接上

3.多列转换成字符串
CREATE TABLE t_col_str AS
SELECT * FROM t_col_row;

这个比较简单，用||或concat函数可以实现：
SELECT concat('a','b') FROM dual;

1)|| OR concat
适用范围：8i,9i,10g及以后版本
SELECT * FROM t_col_str;

SELECT ID,c1||','||c2||','||c3 AS c123
FROM t_col_str;

4.多行转换成字符串
CREATE TABLE t_row_str(
ID INT,
col VARCHAR2(10));

INSERT INTO t_row_str VALUES(1,'a');
INSERT INTO t_row_str VALUES(1,'b');
INSERT INTO t_row_str VALUES(1,'c');
INSERT INTO t_row_str VALUES(2,'a');
INSERT INTO t_row_str VALUES(2,'d');
INSERT INTO t_row_str VALUES(2,'e');
INSERT INTO t_row_str VALUES(3,'c');
COMMIT;

SELECT * FROM t_row_str;

1)MAX + decode
适用范围：8i,9i,10g及以后版本
SELECT id,
?????? MAX(decode(rn, 1, col, NULL)) ||
?????? MAX(decode(rn, 2, ',' || col, NULL)) ||
?????? MAX(decode(rn, 3, ',' || col, NULL)) str
? FROM (SELECT id,
?????????????? col,
?????????????? row_number() over(PARTITION BY id ORDER BY col) AS rn
????????? FROM t_row_str) t
GROUP BY id
ORDER BY 1;

2)row_number + lead
适用范围：8i,9i,10g及以后版本
SELECT id, str
? FROM (SELECT id,
?????????????? row_number() over(PARTITION BY id ORDER BY col) AS rn,
?????????????? col || lead(',' || col, 1) over(PARTITION BY id ORDER BY col) ||
?????????????? lead(',' || col, 2) over(PARTITION BY id ORDER BY col) ||
?????????????? lead(',' || col, 3) over(PARTITION BY id ORDER BY col) AS str
????????? FROM t_row_str)
WHERE rn = 1
ORDER BY 1;

3)MODEL
适用范围：10g及以后版本
SELECT id, substr(str, 2) str FROM t_row_str
MODEL
RETURN UPDATED ROWS
PARTITION BY(ID)
DIMENSION BY(row_number() over(PARTITION BY ID ORDER BY col) AS rn)
MEASURES (CAST(col AS VARCHAR2(20)) AS str)
RULES UPSERT
ITERATE(3) UNTIL( presentv(str[iteration_number+2],1,0)=0)
?????????? (str[0] = str[0] || ',' || str[iteration_number+1])
ORDER BY 1;??????????

4)sys_connect_by_path
适用范围：8i,9i,10g及以后版本
SELECT t.id id, MAX(substr(sys_connect_by_path(t.col, ','), 2)) str
? FROM (SELECT id, col, row_number() over(PARTITION BY id ORDER BY col) rn
????????? FROM t_row_str) t
START WITH rn = 1
CONNECT BY rn = PRIOR rn + 1
?????? AND id = PRIOR id
GROUP BY t.id;

适用范围：10g及以后版本
SELECT t.id id, substr(sys_connect_by_path(t.col, ','), 2) str
? FROM (SELECT id, col, row_number() over(PARTITION BY id ORDER BY col) rn
????????? FROM t_row_str) t
WHERE connect_by_isleaf = 1
START WITH rn = 1
CONNECT BY rn = PRIOR rn + 1
?????? AND id = PRIOR id;

5)wmsys.wm_concat
适用范围：10g及以后版本
这个函数预定义按','分隔字符串，若要用其他符号分隔可以用，replace将','替换。

SELECT id, REPLACE(wmsys.wm_concat(col), ',', '/')
? FROM t_row_str
GROUP BY id;

[ 本帖最后由 zhangfengh 于 2008-7-4 21:49 编辑 ]

?
__________________
我不在江湖，但江湖中有我的传说；
我身在江湖，江湖里却没有我的传说。
只看该作者?????
?
?caizhuoyi
Oracle Stranger

精华贴数 3
个人空间 0
技术积分 1795 (1146)
社区积分 509 (1770)
注册日期 2006-3-1
论坛徽章:16
?????
??????

?#4使用道具? 发表于 2008-7-4 21:16??
接上

5.字符串转换成多列
其实际上就是一个字符串拆分的问题。

CREATE TABLE t_str_col AS
SELECT ID,c1||','||c2||','||c3 AS c123
FROM t_col_str;

SELECT * FROM t_str_col;

1)substr + instr
适用范围：8i,9i,10g及以后版本
SELECT id,
?????? c123,
?????? substr(c123, 1, instr(c123 || ',', ',', 1, 1) - 1) c1,
?????? substr(c123,
????????????? instr(c123 || ',', ',', 1, 1) + 1,
????????????? instr(c123 || ',', ',', 1, 2) - instr(c123 || ',', ',', 1, 1) - 1) c2,
?????? substr(c123,
????????????? instr(c123 || ',', ',', 1, 2) + 1,
????????????? instr(c123 || ',', ',', 1, 3) - instr(c123 || ',', ',', 1, 2) - 1) c3
? FROM t_str_col
ORDER BY 1;

2)regexp_substr
适用范围：10g及以后版本
SELECT id,
?????? c123,
?????? rtrim(regexp_substr(c123 || ',', '.*?' || ',', 1, 1), ',') AS c1,
?????? rtrim(regexp_substr(c123 || ',', '.*?' || ',', 1, 2), ',') AS c2,
?????? rtrim(regexp_substr(c123 || ',', '.*?' || ',', 1, 3), ',') AS c3
? FROM t_str_col
ORDER BY 1;

6.字符串转换成多行
CREATE TABLE t_str_row AS
SELECT id,
?????? MAX(decode(rn, 1, col, NULL)) ||
?????? MAX(decode(rn, 2, ',' || col, NULL)) ||
?????? MAX(decode(rn, 3, ',' || col, NULL)) str
? FROM (SELECT id,
?????????????? col,
?????????????? row_number() over(PARTITION BY id ORDER BY col) AS rn
????????? FROM t_row_str) t
GROUP BY id
ORDER BY 1;

SELECT * FROM t_str_row;

1)UNION ALL
适用范围：8i,9i,10g及以后版本
SELECT id, 1 AS p, substr(str, 1, instr(str || ',', ',', 1, 1) - 1) AS cv
? FROM t_str_row
UNION ALL
SELECT id,
?????? 2 AS p,
?????? substr(str,
????????????? instr(str || ',', ',', 1, 1) + 1,
????????????? instr(str || ',', ',', 1, 2) - instr(str || ',', ',', 1, 1) - 1) AS cv
? FROM t_str_row
UNION ALL
SELECT id,
?????? 3 AS p,
?????? substr(str,
????????????? instr(str || ',', ',', 1, 1) + 1,
????????????? instr(str || ',', ',', 1, 2) - instr(str || ',', ',', 1, 1) - 1) AS cv
? FROM t_str_row
ORDER BY 1, 2;

适用范围：10g及以后版本
SELECT id, 1 AS p, rtrim(regexp_substr(str||',', '.*?' || ',', 1, 1), ',') AS cv
? FROM t_str_row
UNION ALL
SELECT id, 2 AS p, rtrim(regexp_substr(str||',', '.*?' || ',', 1, 2), ',') AS cv
? FROM t_str_row
UNION ALL
SELECT id, 3 AS p, rtrim(regexp_substr(str||',', '.*?' || ',',1,3), ',') AS cv
? FROM t_str_row
ORDER BY 1, 2;

2)VARRAY
适用范围：8i,9i,10g及以后版本
要创建一个可变数组：
CREATE OR REPLACE TYPE ins_seq_type IS VARRAY(8) OF NUMBER;

SELECT * FROM TABLE(ins_seq_type(1, 2, 3, 4, 5));

SELECT t.id,
?????? c.column_value AS p,
?????? substr(t.ca,
????????????? instr(t.ca, ',', 1, c.column_value) + 1,
????????????? instr(t.ca, ',', 1, c.column_value + 1) -
????????????? (instr(t.ca, ',', 1, c.column_value) + 1)) AS cv
? FROM (SELECT id,
?????????????? ',' || str || ',' AS ca,
?????????????? length(str || ',') - nvl(length(REPLACE(str, ',')), 0) AS cnt
????????? FROM t_str_row) t
INNER JOIN TABLE(ins_seq_type(1, 2, 3)) c ON c.column_value <=
???????????????????????????????????????????????????? t.cnt
ORDER BY 1, 2;

3)SEQUENCE series
这类方法主要是要产生一个连续的整数列，产生连续整数列的方法有很多，主要有：
CONNECT BY,ROWNUM+all_objects,CUBE等。
适用范围：8i,9i,10g及以后版本
SELECT t.id,
?????? c.lv AS p,
?????? substr(t.ca,
????????????? instr(t.ca, ',', 1, c.lv) + 1,
????????????? instr(t.ca, ',', 1, c.lv + 1) -
????????????? (instr(t.ca, ',', 1, c.lv) + 1)) AS cv
? FROM (SELECT id,
?????????????? ',' || str || ',' AS ca,
?????????????? length(str || ',') - nvl(length(REPLACE(str, ',')), 0) AS cnt
????????? FROM t_str_row) t,
?????? (SELECT LEVEL lv FROM dual CONNECT BY LEVEL <= 5) c
WHERE c.lv <= t.cnt
ORDER BY 1, 2;

SELECT t.id,
?????? c.rn AS p,
?????? substr(t.ca,
????????????? instr(t.ca, ',', 1, c.rn) + 1,
????????????? instr(t.ca, ',', 1, c.rn + 1) -
????????????? (instr(t.ca, ',', 1, c.rn) + 1)) AS cv
? FROM (SELECT id,
?????????????? ',' || str || ',' AS ca,
?????????????? length(str || ',') - nvl(length(REPLACE(str, ',')), 0) AS cnt
????????? FROM t_str_row) t,
?????? (SELECT rownum rn FROM all_objects WHERE rownum <= 5) c
WHERE c.rn <= t.cnt
ORDER BY 1, 2;

SELECT t.id,
?????? c.cb AS p,
?????? substr(t.ca,
????????????? instr(t.ca, ',', 1, c.cb) + 1,
????????????? instr(t.ca, ',', 1, c.cb + 1) -
????????????? (instr(t.ca, ',', 1, c.cb) + 1)) AS cv
? FROM (SELECT id,
?????????????? ',' || str || ',' AS ca,
?????????????? length(str || ',') - nvl(length(REPLACE(str, ',')), 0) AS cnt
????????? FROM t_str_row) t,
?????? (SELECT rownum cb FROM (SELECT 1 FROM dual GROUP BY CUBE(1, 2))) c
WHERE c.cb <= t.cnt
ORDER BY 1, 2;

适用范围：10g及以后版本
SELECT t.id,
?????? c.lv AS p,
?????? rtrim(regexp_substr(t.str || ',', '.*?' || ',', 1, c.lv), ',') AS cv
? FROM (SELECT id,
?????????????? str,
?????????????? length(regexp_replace(str || ',', '[^' || ',' || ']', NULL)) AS cnt
????????? FROM t_str_row) t
INNER JOIN (SELECT LEVEL lv FROM dual CONNECT BY LEVEL <= 5) c ON c.lv <=
?????????????????????????????????????????????????????????????????? t.cnt
ORDER BY 1, 2;

4)Hierarchical + DBMS_RANDOM
适用范围：10g及以后版本
SELECT id,
?????? LEVEL AS p,
?????? rtrim(regexp_substr(str || ',', '.*?' || ',', 1, LEVEL), ',') AS cv
? FROM t_str_row
CONNECT BY id = PRIOR id
?????? AND PRIOR dbms_random.VALUE IS NOT NULL
?????? AND LEVEL <=
?????????? length(regexp_replace(str || ',', '[^' || ',' || ']', NULL))
ORDER BY 1, 2;

5)Hierarchical + CONNECT_BY_ROOT
适用范围：10g及以后版本
SELECT id,
?????? LEVEL AS p,
?????? rtrim(regexp_substr(str || ',', '.*?' || ',', 1, LEVEL), ',') AS cv
? FROM t_str_row
CONNECT BY id = connect_by_root id
?????? AND LEVEL <=
?????????? length(regexp_replace(str || ',', '[^' || ',' || ']', NULL))
ORDER BY 1, 2;

6)MODEL
适用范围：10g及以后版本
SELECT id, p, cv FROM t_str_row
MODEL
RETURN UPDATED ROWS
PARTITION BY(ID)
DIMENSION BY( 0 AS p)
MEASURES( str||',' AS cv)
RULES UPSERT
? (cv
?? [ FOR p
??????? FROM 1 TO length(regexp_replace(cv[0],'[^'||','||']',null))
??????? INCREMENT 1
?? ] = rtrim(regexp_substr( cv[0],'.*?'||',',1,cv(p)),','))
ORDER BY 1,2;

end.
?
?

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