Oracle中的聚合函数 rank() rank() over(partition by A order by B asc|desc)A为分集字段,B为集内排序字段典型案例:找出某个日期每个营业部内资产数额排名前两位的顾客
select * from (select rank() over(partition by branch_no order by asset desc) rk,account,asset from aa.asset)where rk<=2