一个简单的登陆有关问题

一个简单的登陆问题?
IUserDao

Java code

public interface IUserDao {        public User queryByUserNameAndPassword(String userName, String password) throws Exception;}

UserDao

Java code

public User queryByUserNameAndPassword(String userName, String password)            throws Exception {        String hql = "FROM User as u WHERE u.userName=? and u.password=?";           String[] str = new String[] {userName, password};           List<User> users = this.getHibernateTemplate().find(hql, str);           if (users != null && users.size() >= 1) {               return users.get(1);           } else {               return null;           }            }

IUserService

Java code

 public String isLogin(String userName, String password) throws  Exception;

userService

Java code

public String isLogin(String userName, String password) throws Exception {         User user = userDao.queryByUserNameAndPassword(userName, password);           if(user != null) {               return user.getUserName();           } else {               return null;           }    }

UserAction

Java code

        public String execute() throws Exception {          if (isInvalid(user.getUserName())) {               this.addFieldError("uid", "登录ID不能为空");               return INPUT;           }           if (isInvalid(user.getPassword())) {               this.addFieldError("password", "密码项不能为空");               return INPUT;           }           String uname = userService.isLogin(user.getUserName(), user.getPassword());           if (uname != null) {               Map session = ActionContext.getContext().getSession();               session.put("uname", uname);               session.put("uid", user.getUid());               return SUCCESS;           } else {               this.addFieldError("idorpassword", "用户名或密码错误");               return INPUT;           }        }    private boolean isInvalid(String userName) {        // TODO Auto-generated method stub        return false;    }

不够写了 在下面


[解决办法]
初始化action有错误，也就是说你的action对应累的函数处理有问题，你好好查查
[解决办法]
<action name="login" class="userAction">


<bean id="userAction" class="com.action.UserAction">
<property name="userService" ref="userService"></property>
</bean>

不能这样注入action的吧
[解决办法]
<constant name="struts.objectFactory.spring.autoWire" value="name" />

定义一下这个常量， 让spring自动按名字注入service
[解决办法]
美女，sessionFactory配置错误。
<bean id="sessionFactory"
class="org.springframework.orm.hibernate3.LocalSessionFactoryBean">
</bean>
把这个加上

------解决方案--------------------

userAction这样配置，少了一个"/"
<bean id="/userAction" class="com.action.UserAction">
<property name="userService" ref="userService"></property>
</bean>

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