关于java读取xml文件请问

关于java读取xml文件请教
如下xml文件
<?................?>

<users>
  <user name="one">
  <username>one</username>
  <password>123</password>
  <user>
  <user name="two">
  <username>two</username>
  <password>123</password>
  <user>

  <user name="three">
  <username>three</username>
  <password>123</password>
  <user>
</users>

我想根据user节点的name属性，取得每个user下面的username和password，代码该如何写呢？谢谢

[解决办法]

Java code

package com.ss;import java.io.IOException;import java.net.URL;import java.util.List;import org.jdom.Document;import org.jdom.Element;import org.jdom.JDOMException;import org.jdom.input.SAXBuilder;public class ParseXml{    public static void main(String[] args)    {    SAXBuilder builder = new SAXBuilder(false);    String xml="user.xml";//这个路径表示跟当前类在同一个package下    URL url = ParseXml.class.getResource(xml);    Document doc;    try    {        doc = builder.build(url);        Element dataset = doc.getRootElement();        List userList = dataset.getChildren();        for(int i=0;i<userList.size();i++)        {        Element user = (Element)userList.get(i);        Element userName =(Element)user.getChildren().get(0);        Element password =(Element)user.getChildren().get(1);        System.out.println("username:" +userName.getText() +"  password:"+password.getText());        }            }    catch (JDOMException e)    {         e.printStackTrace();    }    catch (IOException e)    {        e.printStackTrace();    }    }}
[解决办法]
Java code
public static void readxmlFile() {        String fileName = "etc/abc.xml";        Element element = null;        File f = new File(fileName);        DocumentBuilder db = null;        DocumentBuilderFactory dbf = null;        try {            dbf = DocumentBuilderFactory.newInstance();            db = dbf.newDocumentBuilder();            Document dt = db.parse(f);            element = dt.getDocumentElement();            NodeList childNodes = element.getChildNodes();            String userName = "";            String password = "";            for (int i = 0; i < childNodes.getLength(); i++) {                Node node1 = childNodes.item(i);                if ("user".equals(node1.getNodeName())) {                    NodeList nodeDetail = node1.getChildNodes();                     for (int j = 0; j < nodeDetail.getLength(); j++) { // 遍历<users>下的节点                        Node detail = nodeDetail.item(j); // 获得<users>元素每一个节点                        if ("username".equals(detail.getNodeName()))                             userName = detail.getTextContent();                        else if ("password".equals(detail.getNodeName())) {                            password = detail.getTextContent();                        }                    }                    System.out.println("userName:" + userName + " password:"                            + password);                }            }        } catch (Exception e) {            e.printStackTrace();        }    }
[解决办法]
可以直接使用java自带的DOM解析方式
[解决办法]
dom4j xpath解析很方便
[解决办法]
dom4j