请问该sql查询语句该如何写

请教该sql查询语句该怎么写
现有表：a
数据：
商品id 商品属性id 字符值 数字值
sid cid stringvalue intvalue
10001000 3
10001001 0,2,5,12, 0
10001002 3

10031000 2
10031001 0,1,4,5,7,13, 0
10031002 2


现要查询满足条件的sid，查询所有商品中属性1000(cid)值<=3，并且属性1001(cid)值为like '%,5,%'的记录，然后根据sid distinct去重。
按照上面逻辑描述写(cid=1000 and intvalue<=3) and (cid=1001 and stringvalue like '%,5,%')，这样只返回一条记录
逻辑有点复杂，我是已经绕不出来了，麻烦各位高手。

[解决办法]

SQL code

Select Distinct [sid] From 表a Where()
[解决办法]
SQL code
select distinct t1.sid from a t1where exists (select 1 from a t2 where t2.sid=t1.sid and t2.cid=1000 and t2.intvalue<=3)and exists (select 1 from a t3 where t3.sid=t1.sid and t3.cid=1001 and t3.stringvalue like '%,5,%')
[解决办法]
SQL code
IF EXISTS (SELECT 1 FROM SYSOBJECTS WHERE name = 'A')BEGIN    DROP TABLE AENDGOCREATE TABLE A(    sid INT,    cid INT,    stringvalue  VARCHAR(100),    intvalue INT)INSERT INTO ASELECT 1000, 1000, '',3 UNIONSELECT 1000, 1001, '0,2,5,12,', 0 UNIONSELECT 1000, 1002, '',3 UNIONSELECT 1001, 1000, '',4 UNIONSELECT 1001, 1001, '0,2,5,12,', 0 UNIONSELECT 1001, 1002, '',3 UNIONSELECT 1003, 1000, '',2 UNIONSELECT 1003, 1001, '0,1,4,5,7,13,', 0 UNIONSELECT 1003, 1002, '',2SELECT sid FROM AWHERE cid=1000 and intvalue<=3INTERSECTSELECT Sid FROM AWHERE cid=1001 and stringvalue like '%,5,%'sid10001003
[解决办法]
SQL code
--> 测试数据：[test]if object_id('[test]') is not null drop table [test]create table [test]([sid] int,[cid] int,[stringvalue] varchar(13),[intvalue] int)insert [test]select 1000,1000,'3',null union allselect 1000,1001,'0,2,5,12,',0 union allselect 1000,1002,'3',null union allselect 1003,1000,'2',null union allselect 1003,1001,'0,1,4,5,7,13,',0 union allselect 1003,1002,'2',null--你的只需把 and 改成or即可select * from testwhere (cid=1000 and intvalue<=3) or (cid=1001 and stringvalue like '%,5,%')/*sid    cid    stringvalue    intvalue1000    1001    0,2,5,12,    01003    1001    0,1,4,5,7,13,    0*/