请问个有关问题，这段代码为什么只取得到第一行呀

请教个问题，这段代码为什么只取得到第一行呀

C/C++ code

#include <stdio.h>void echoarraytoline(char *arr[]);main(){     char *arr[3] = {          "dasdsadadadaa",          "dasdasdsadsaddsadsadsadas",          "fsdfdsfsdfsfsdsadsa",          "fsdfsgghfhfghdsadsadsa"     };     echoarraytoline(arr);     system( "pause ");}void echoarraytoline(char *arr[3]){     int i = 0;     int j = 0;     int c = 0;          while( c = *(*(arr+i)+j++) ){            if( i == 4 ){               break;                }else{                   if( c != '\0'){                       printf("%c" , c );                       printf("/");                                          }else{                              i++;                       j=0;                       printf("end");                   }            }          }}

C/C++ code

void echoarraytoline(char *arr[3]){     int i = 0;     int j = 0;     int c = 0;          while( c = *(*(arr+i)+j++) ) //c=='\0'while就退出了{            if( i == 4 ){               break;                }else{                   if( c != '\0'){                       printf("%c" , c );                       printf("/");                                          }else{                              i++;                       j=0;                       printf("end");                   }            }          }}
[解决办法]
解答完成了。
[解决办法]
“多一少一”问题占程序员常犯错误的10%以上！