表字段值与另一表字段名相同问题。
现有表A:
A1 A2 A3
1 2 工资
2 3 分红
3 1 奖金
表B:
工资 奖金 加班工资 分红 ....（还有很多其他字段）
1 3 1 2
2 2 3 2
3 1 3 3
怎样根据表A的A3字段值将表B里对应字段名（表A的A3字段值为表B的全部字段名的一部分）的内容取出来？求高手指点一二！感激不尽！！
[解决办法]
猜 lz 要的是这个？
mysql> select * from config;+----+----------+| id | name |+----+----------+| 1 | salary || 2 | bonus || 3 | overtime |+----+----------+3 rows in set (0.00 sec)mysql> select * from data;+--------+-------+----------+| salary | bonus | overtime |+--------+-------+----------+| 1 | 2 | 4 || 3 | 3 | 3 |+--------+-------+----------+2 rows in set (0.00 sec)mysql> select @sql := concat("select ", group_concat(name), " from data;") -> from config -> where id in (1, 2);+--------------------------+| @sql := concat("select ", group_concat(name), " from data;") |+--------------------------+| select salary,bonus from data; |+--------------------------+1 row in set (0.00 sec)mysql>mysql> prepare sp from @sql;Query OK, 0 rows affected (0.00 sec)Statement preparedmysql> execute sp;+--------+-------+| salary | bonus |+--------+-------+| 1 | 2 || 3 | 3 |+--------+-------+2 rows in set (0.00 sec)mysql> drop prepare sp;Query OK, 0 rows affected (0.00 sec)
[解决办法]
http://blog.csdn.net/acmain_chm/article/details/4283943
MySQL交叉表
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