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下面这个程序只能输入3x-8或5s+18,怎样改才能直接输3x-8=0和5s+18=0解决办法

2012-04-18 
下面这个程序只能输入3x-8或5s+18,怎样改才能直接输3x-80和5s+180#include iostream.h#includestdlib

下面这个程序只能输入3x-8或5s+18,怎样改才能直接输3x-8=0和5s+18=0
#include <iostream.h>
#include"stdlib.h"  
class CEquation
{
private:
double a; // 未知数系数
double b; // 常数项
char unknown; // 未知数的符号
public:
CEquation(double aa=0,double bb=0);
friend istream &operator >> (istream &in,CEquation &e);
friend ostream &operator << (ostream &out,CEquation &e);
double Solve();
char getUnknown();
};
CEquation::CEquation(double aa,double bb)
{
a=aa;
b=bb;
}
istream &operator >> (istream &in,CEquation &e)//在两次测试中,分别输入3x-8=0和5s+18=0
{
in>>e.a >>e.unknown>>e.b;
return in;
}
ostream &operator << (ostream &out,CEquation &e)
{
if(e.b >=0)
{
out<<e.a <<'x'<<'+'<<e.b<<'='<<'0'<<endl;
}
else
{
out<<e.a <<'x'<<e.b<<'='<<'0'<<endl; 
}
return out;
}
double CEquation::Solve()
{
return ((-b)/a);
}

char CEquation::getUnknown()
{
return unknown;
}
int main()
{
CEquation e,m;
cout<<"请输入一元一次方程(输入格式:3x-8=0):";
cin>>e;  
cout<<"方程为:"<<e;
cout<<"方程的解为:"<<e.getUnknown()<<"="<<e.Solve()<<endl; //对两次测试,分别输出x=...和s=...
cout<<"请输入一元一次方程(输入格式:5s+18=0):";
cin>>m;  
cout<<"方程为:"<<m;
cout<<"方程的解为:"<<m.getUnknown()<<"="<<m.Solve()<<endl; //对两次测试,分别输出x=...和s=...
m.Solve ();
return 0;
}


[解决办法]
用05,10编译都出错,代码有问题,1>c:\documents and settings\administrator\桌面\s\s.cpp(2) : fatal error C1083: Cannot open include file: 'iostream.h': No such file or directory
楼主用6.0编译的吧,6.0不太标准,尽量少用
[解决办法]
#include "stdafx.h"
#include <iostream>
#include <stdio.h>
#include"stdlib.h" 
using namespace std;
class CEquation
{
private:
double a; // 未知数系数
double b; // 常数项
char unknown; // 未知数的符号

public:
CEquation(double aa=0,double bb=0);
friend istream &operator >> (istream &in,CEquation &e);
friend ostream &operator << (ostream &out,CEquation &e);
double Solve();
char getUnknown();
};

CEquation::CEquation(double aa,double bb)
{
a=aa;
b=bb;
}

istream &operator >> (istream &in,CEquation &e)//在两次测试中,分别输入3x-8=0和5s+18=0
{
in>>e.a >>e.unknown>>e.b;
return in;
}

ostream &operator << (ostream &out,CEquation &e)
{
if(e.b >=0)
{
out<<e.a <<'x'<<'+'<<e.b<<'='<<'0'<<endl;
}
else
{
out<<e.a <<'x'<<e.b<<'='<<'0'<<endl;
}
return out;
}

double CEquation::Solve()
{
return ((-b)/a);
}

char CEquation::getUnknown()
{
return unknown;
}
int main()
{
CEquation e,m;
cout<<"请输入一元一次方程(输入格式:3x-8=0):";
cin>>e;
cout<<"方程为:"<<e;
cout<<"方程的解为:"<<e.getUnknown()<<"="<<e.Solve()<<endl; //对两次测试,分别输出x=...和s=...
fflush( stdin );
cout<<"请输入一元一次方程(输入格式:5s+18=0):";
cin>>m;
cout<<"方程为:"<<m;
cout<<"方程的解为:"<<m.getUnknown()<<"="<<m.Solve()<<endl; //对两次测试,分别输出x=...和s=...


m.Solve ();
return 0;
}
错误纠正后的程序

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