string 数组 删除重复并统计解决办法

string 数组 删除重复并统计
我有一个string数组中文的 如何删除其中的重复项，并统计重复项的数目
比如String[] old ="类目一','类目二','类目三','类目一','类目三'";
如何得到一个新数组string [] new= ="'类目一','类目二','类目三'";
并得到类目一个数 2  
类目二 个数1 类目三个数2

[解决办法]

Java code

String[] old = { "类目一", "类目二", "类目三", "类目一", "类目三" };        List<String> list = new ArrayList<String>();        for (String str : old) {            if (!list.contains(str)) {                list.add(str);            }        }        String[] dest = new String[list.size()];        list.toArray(dest);        for (String str : dest) {            System.out.println(str);        }
[解决办法]
1楼可以，另外用map也可以，不用判断。
[解决办法]
自己看着需要修改。。。

Java code
    public static void main(String[] args) throws Exception {        String[] old = { "类目一", "类目二", "类目三", "类目一", "类目三" };        Map<String, Integer> map = new TreeMap<String, Integer>();        for (String key : old) {            if (map.containsKey(key)) {                map.put(key, map.get(key) + 1);            } else {                map.put(key, 1);            }        }        String[] des = new String[map.size()];        int i = 0;        for (String key : map.keySet()) {            des[i++] = key + " : " + map.get(key);        }        System.out.println(Arrays.toString(des));    }
[解决办法]

Java code
public static String[] replace(String[] array, Map<String, Integer> map) {        if (array != null && array.length > 0) {            int len = array.length, v = 0;            for (int i = 0; i < len; i++) {                if (map.containsKey(array[i])) {                    v = map.get(array[i]);                    map.put(array[i], v + 1);                } else                    map.put(array[i], 1);            }            //            System.out.println(map.entrySet());            return map.keySet().toArray(new String[map.keySet().size()]);        }        return array;    }  public static void main(String[] args) {        String[] old = new String[] { "类目一", "类目二", "类目三", "类目一", "类目三" };        Map<String, Integer> map = new HashMap<String, Integer>();        print(replace(old, map));        System.out.println(map);        //        print(old);    }
[解决办法]
Java code
String[] old = { "类目一", "类目二", "类目三", "类目一", "类目三" };Map<String,Integer> map = new HashMap<String,Integer>();        for(int i =0;i<old.length;i++){  if(!map.containsKey(old[i]))     map.put(old[i], 1);  else    map.put(old[i], map.get(old[i]+1));}