这个该怎么写呢
A表 X字段内容 3,5,7
B表 Num Name
1 abc
2 abc
3 abc
4 abc
5 abc
6 abc
7 abc
8 abc
inner join 查询时候 能获取到 3,5,7对应的Name值
或者要怎么解决。。先谢谢了
[解决办法]
分解字符串包含的信息值后然后合并到另外一表的信息(爱新觉罗.毓华(十八年风雨,守得冰山雪莲花开) 2007-12-23 广东深圳)/*问题描述tbaID classid name1 1,2,3 西服 2 2,3 中山装3 1,3 名裤tbb id classname1 衣服2 上衣3 裤子我得的结果是id classname name1 衣服,上衣,裤子 西服 2 上衣，裤子 中山装3 衣服，裤子 名裤*/-------------------------------------------------------sql server 2000中的写法create table tba(ID int,classid varchar(20),name varchar(10))insert into tba values(1,'1,2,3','西服')insert into tba values(2,'2,3' ,'中山装')insert into tba values(3,'1,3' ,'名裤')create table tbb(ID varchar(10), classname varchar(10))insert into tbb values('1','衣服')insert into tbb values('2','上衣')insert into tbb values('3','裤子')go--第1种方法，创建函数来显示create function f_hb(@id varchar(10))returns varchar(1000)asbegin declare @str varchar(1000) set @str='' select @str=@str+','+[classname] from tbb where charindex(','+cast(id as varchar)+',',','+@id+',')>0 return stuff(@str,1,1,'')endgo select id,classid=dbo.f_hb(classid),name from tbadrop function f_hb/*id classid name ----------- ------------- ---------- 1 衣服,上衣,裤子 西服2 上衣,裤子 中山装3 衣服,裤子 名裤（所影响的行数为 3 行）*/--第2种方法.updatewhile(exists (select * from tba,tbb where charindex(tbb.id,tba.classid) >0))update tbaset classid= replace(classid,tbb.id,tbb.classname)from tbbwhere charindex(tbb.id,tba.classid)>0select * from tba/*ID classid name ----------- -------------------- ---------- 1 衣服,上衣,裤子 西服2 上衣,裤子 中山装3 衣服,裤子 名裤（所影响的行数为 3 行）*/drop table tba,tbb--------------------------------------sql server 2005中先分解tba中的classid,然后再合并classnamecreate table tba(ID int,classid varchar(20),name varchar(10))insert into tba values(1,'1,2,3','西服')insert into tba values(2,'2,3' ,'中山装')insert into tba values(3,'1,3' ,'名裤')create table tbb(ID varchar(10), classname varchar(10))insert into tbb values('1','衣服')insert into tbb values('2','上衣')insert into tbb values('3','裤子')goSELECT id , classname , name FROM( SELECT DISTINCT id , name FROM (select tbc.id , tbc.name , tbb.classname from ( SELECT A.id , A.name , B.classid FROM(SELECT id , name , [classid] = CONVERT(xml,'<root><v>' + REPLACE([classid], ',', '</v><v>') + '</v></root>') FROM tba)A OUTER APPLY(SELECT classid = N.v.value('.', 'varchar(100)') FROM A.[classid].nodes('/root/v') N(v))B ) tbc , tbb where tbc.classid = tbb.id ) T)A OUTER APPLY( SELECT [classname]= STUFF(REPLACE(REPLACE(( SELECT classname FROM (select tbc.id , tbc.name , tbb.classname from ( SELECT A.id , A.name , B.classid FROM(SELECT id , name , [classid] = CONVERT(xml,'<root><v>' + REPLACE([classid], ',', '</v><v>') + '</v></root>') FROM tba)A OUTER APPLY(SELECT classid = N.v.value('.', 'varchar(100)') FROM A.[classid].nodes('/root/v') N(v))B ) tbc , tbb where tbc.classid = tbb.id ) N WHERE id = A.id and name = A.name FOR XML AUTO), '<N classname="', ','), '"/>', ''), 1, 1, ''))Norder by iddrop table tba,tbb/*id classname name----------- -------------- ----------1 衣服,上衣,裤子 西服2 上衣,裤子 中山装3 衣服,裤子 名裤(3 行受影响)*/自己修改一下吧唐诗哥哥回家吃饭去了
[解决办法]
goif object_id('[A1]') is not null drop table [A1]gocreate table [A1]([ID] varchar(1),[X] varchar(5))goinsert [A1]select '1','3,5,7'--> 测试数据：[B2]goif object_id('[B2]') is not null drop table [B2]gocreate table [B2]([Num] varchar(2),[Name] varchar(3))goinsert [B2]select '1','abc' union allselect '2','abc' union allselect '3','abc' union allselect '4','abc' union allselect '5','abc' union allselect '6','abc' union allselect '7','abc' union allselect '8','abc'gocreate function f_hb(@id varchar(10))returns varchar(1000)asbegin declare @str varchar(1000) set @str='' select @str=@str+','+[Name] from [B2] where charindex(','+cast([Num] as varchar)+',',','+@id+',')>0 return stuff(@str,1,1,'')endgo select classid=dbo.f_hb([X]) from [A1]/*classidabc,abc,abc*/