我想把查询的记录合为一条怎么办？
例如：查询结果为
MemberID Name Sex Email Interest000001 张三 男 aaa@hao.com 打球000001 张三 男 aaa@hao.com 游泳000001 张三 男 bbb@hao.com 看电影
MemberID Name Sex Email Interest000001 张三 男 aaa@hao.com 打球、游泳、看电影
create table T1(code varchar(50),[name] varchar(50),dec varchar(50))create table T2(code varchar(50),mark varchar(50))insert into T1 select '1002',' 内存1',' 测试1' insert into T2 values('1002' ,'备注1001' ) insert into T2 values('1002' ,'备注1002v88' )insert into T2 values('1003 ','备注1002v55' )insert into T2 values('1002' ,'备注1002v1 ' ) insert into T2 values('1006' ,'备注1006' ) select T1.code,T1.name,T1.dec,REPLACE((select ','+mark from T1 for xml path('')),',备注','') from T1 left join T2 ON T1.code=T2.code where T2.mark ='备注1001' declare @strs varchar(100) set @strs=''; select @strs=@strs+ mark from T2 select T1.code,T1.name,T1.dec, replace (@strs,'备注','') from T1 code name dec -------------------------------------------------- -------------------------------------------------- -------------------------------------------------- ----------------------------------------------------------------------------------------------------------------1002 内存1 测试1 1001(1 行受影响)code name dec -------------------------------------------------- -------------------------------------------------- -------------------------------------------------- ----------------------------------------------------------------------------------------------------------------1002 内存1 测试1 10011002v881002v551002v1 1006(1 行受影响)
[解决办法]
if object_id('tb') is not null drop table tbgocreate table tb( MemberID varchar(10), Name varchar(10), Sex varchar(10), Email varchar(20), Interest varchar(10))goinsert into tbselect '000001','张三','男','aaa@hao.com','打球' union allselect '000001','张三','男','aaa@hao.com','游泳' union allselect '000001','张三','男','aaa@hao.com','看电影'goselect MemberID,Name=Max(Name),Sex=Max(Sex),Email=Max(Email), Interest=stuff((select ','+Interest from tb where MemberID=a.MemberID for xml path('')),1,1,'') from tb a group by MemberIDgo/*MemberID Name Sex Email Interest---------- ---------- ---------- -------------------- ----------------------------------------------------------------------------------------------------------------000001 张三 男 aaa@hao.com 打球,游泳,看电影(1 行受影响)*/
[解决办法]
合并列值 --*******************************************************************************************表结构，数据如下： id value ----- ------ 1 aa 1 bb 2 aaa 2 bbb 2 ccc 需要得到结果： id values ------ ----------- 1 aa,bb 2 aaa,bbb,ccc 即：group by id, 求 value 的和（字符串相加） 1. 旧的解决方法(在sql server 2000中只能用函数解决。) --=============================================================================create table tb(id int, value varchar(10)) insert into tb values(1, 'aa') insert into tb values(1, 'bb') insert into tb values(2, 'aaa') insert into tb values(2, 'bbb') insert into tb values(2, 'ccc') go --1. 创建处理函数 CREATE FUNCTION dbo.f_strUnite(@id int) RETURNS varchar(8000) AS BEGIN DECLARE @str varchar(8000) SET @str = '' SELECT @str = @str + ',' + value FROM tb WHERE id=@id RETURN STUFF(@str, 1, 1, '') END GO -- 调用函数 SELECt id, value = dbo.f_strUnite(id) FROM tb GROUP BY id drop table tb drop function dbo.f_strUnite go/* id value ----------- ----------- 1 aa,bb 2 aaa,bbb,ccc （所影响的行数为 2 行） */ --===================================================================================2. 新的解决方法(在sql server 2005中用OUTER APPLY等解决。) create table tb(id int, value varchar(10)) insert into tb values(1, 'aa') insert into tb values(1, 'bb') insert into tb values(2, 'aaa') insert into tb values(2, 'bbb') insert into tb values(2, 'ccc') go -- 查询处理 SELECT * FROM(SELECT DISTINCT id FROM tb)A OUTER APPLY( SELECT [values]= STUFF(REPLACE(REPLACE( ( SELECT value FROM tb N WHERE id = A.id FOR XML AUTO ), ' <N value="', ','), '"/>', ''), 1, 1, '') )N drop table tb /* id values ----------- ----------- 1 aa,bb 2 aaa,bbb,ccc (2 行受影响) */ --SQL2005中的方法2 create table tb(id int, value varchar(10)) insert into tb values(1, 'aa') insert into tb values(1, 'bb') insert into tb values(2, 'aaa') insert into tb values(2, 'bbb') insert into tb values(2, 'ccc') go select id, [values]=stuff((select ','+[value] from tb t where id=tb.id for xml path('')), 1, 1, '') from tb group by id /* id values ----------- -------------------- 1 aa,bb 2 aaa,bbb,ccc (2 row(s) affected) */ drop table tb /*标题：分拆列值1作者：爱新觉罗.毓华(十八年风雨,守得冰山雪莲花开)时间：2008-11-20地点：广东深圳描述有表tb, 如下:id value----------- -----------1 aa,bb2 aaa,bbb,ccc欲按id,分拆value列, 分拆后结果如下:id value----------- --------1 aa1 bb2 aaa2 bbb2 ccc*/--1. 旧的解决方法(sql server 2000)SELECT TOP 8000 id = IDENTITY(int, 1, 1) INTO # FROM syscolumns a, syscolumns b SELECT A.id, value = SUBSTRING(A.[value], B.id, CHARINDEX(',', A.[value] + ',', B.id) - B.id)FROM tb A, # BWHERE SUBSTRING(',' + A.[value], B.id, 1) = ','DROP TABLE #--2. 新的解决方法(sql server 2005) create table tb(id int,value varchar(30))insert into tb values(1,'aa,bb')insert into tb values(2,'aaa,bbb,ccc')goSELECT A.id, B.valueFROM( SELECT id, [value] = CONVERT(xml,'<root><v>' + REPLACE([value], ',', '</v><v>') + '</v></root>') FROM tb)AOUTER APPLY( SELECT value = N.v.value('.', 'varchar(100)') FROM A.[value].nodes('/root/v') N(v))BDROP TABLE tb/*id value----------- ------------------------------1 aa1 bb2 aaa2 bbb2 ccc(5 行受影响)*/
[解决办法]
create table xp447196763(MemberID varchar(8), name varchar(4), Sex varchar(4), Email varchar(15), Interest varchar(8))insert into xp447196763select '000001', '张三', '男', 'aaa@hao.com', '打球' union allselect '000001', '张三', '男', 'aaa@hao.com', '游泳' union allselect '000001', '张三', '男', 'aaa@hao.com', '看电影'declare @Interests varchar(50)=''select @Interests=@Interests+Interest+'、'from xp447196763select MemberID,name,Sex,Email,left(@Interests,len(@Interests)-1) Interestfrom xp447196763group by MemberID,name,Sex,EmailMemberID name Sex Email Interest-------- ---- ---- --------------- --------------------------------------------------000001 张三 男 aaa@hao.com 打球、游泳、看电影(1 row(s) affected)