怎么达到这个效果

如何达到这个效果？

35AAA 
47AAA  
51AAA  
36BBB
35BBB 
47BBB
……
===>

AAA 35,47,51
BBB 36,35,47
……
求大侠帮助，谢谢。


[解决办法]

SQL code

合并列值 --*******************************************************************************************表结构，数据如下： id    value ----- ------ 1    aa 1    bb 2    aaa 2    bbb 2    ccc 需要得到结果： id    values ------ ----------- 1      aa,bb 2      aaa,bbb,ccc 即：group by id, 求 value 的和（字符串相加） 1. 旧的解决方法(在sql server 2000中只能用函数解决。) --=============================================================================create table tb(id int, value varchar(10)) insert into tb values(1, 'aa') insert into tb values(1, 'bb') insert into tb values(2, 'aaa') insert into tb values(2, 'bbb') insert into tb values(2, 'ccc') go --1. 创建处理函数 CREATE FUNCTION dbo.f_strUnite(@id int) RETURNS varchar(8000) AS BEGIN     DECLARE @str varchar(8000)     SET @str = ''     SELECT @str = @str + ',' + value FROM tb WHERE id=@id     RETURN STUFF(@str, 1, 1, '') END GO -- 调用函数 SELECt id, value = dbo.f_strUnite(id) FROM tb GROUP BY id drop table tb drop function dbo.f_strUnite go/* id          value      ----------- ----------- 1          aa,bb 2          aaa,bbb,ccc （所影响的行数为 2 行） */ --===================================================================================2. 新的解决方法(在sql server 2005中用OUTER APPLY等解决。) create table tb(id int, value varchar(10)) insert into tb values(1, 'aa') insert into tb values(1, 'bb') insert into tb values(2, 'aaa') insert into tb values(2, 'bbb') insert into tb values(2, 'ccc') go -- 查询处理 SELECT * FROM(SELECT DISTINCT id FROM tb)A OUTER APPLY(         SELECT [values]= STUFF(REPLACE(REPLACE(             (                 SELECT value FROM tb N                 WHERE id = A.id                 FOR XML AUTO             ), ' <N value="', ','), '"/>', ''), 1, 1, '') )N drop table tb /* id          values ----------- ----------- 1          aa,bb 2          aaa,bbb,ccc (2 行受影响) */ --SQL2005中的方法2 create table tb(id int, value varchar(10)) insert into tb values(1, 'aa') insert into tb values(1, 'bb') insert into tb values(2, 'aaa') insert into tb values(2, 'bbb') insert into tb values(2, 'ccc') go select id, [values]=stuff((select ','+[value] from tb t where id=tb.id for xml path('')), 1, 1, '') from tb group by id /* id          values ----------- -------------------- 1          aa,bb 2          aaa,bbb,ccc (2 row(s) affected) */
[解决办法]
SQL code
select COl1,col2=stuff((select ','+col2 from t1 where COl1=a.COl1 for xml path('')),1,1,'')from t1 as agroup by col1
[解决办法]
SQL code
create table tb(c1 int,c2 varchar(10))insert into tb select 35,'AAA'insert into tb select 47,'AAA'   insert into tb select 51,'AAA'   insert into tb select 36,'BBB'insert into tb select 35,'BBB'  insert into tb select 47,'BBB'goselect c2,stuff((select ','+LTRIM(c1) from tb where c2=a.c2 for xml path('')),1,1,'')c1 from tb a group by c2/*c2         c1---------- ----------------------------------------------------------------------------------------------------------------AAA        35,47,51BBB        36,35,47(2 行受影响)*/godrop table tb
[解决办法]
SQL code
use Tempdbgo--> -->  declare @T table([Col2] int,[Col1] nvarchar(3))Insert @Tselect 35,N'AAA' union allselect 47,N'AAA' union allselect 51,N'AAA' union allselect 36,N'BBB' union allselect 35,N'BBB' union allselect 47,N'BBB' select COl1,col2=stuff((select ','+RTRIM(col2) from @T where COl1=a.COl1 for xml path('')),1,1,'')from @T as agroup by col1/*COl1    col2AAA    35,47,51BBB    36,35,47*/ 
 
[解决办法]
SQL code
------------------------------ Author  :fredrickhu(小F，向高手学习)-- Date    :2011-11-03 14:43:24-- Version:--      Microsoft SQL Server 2008 R2 (RTM) - 10.50.1617.0 (Intel X86) --    Apr 22 2011 11:57:00 --    Copyright (c) Microsoft Corporation--    Enterprise Evaluation Edition on Windows NT 6.1 <X64> (Build 7600: ) (WOW64)--------------------------------> 测试数据：[tb]if object_id('[tb]') is not null drop table [tb]go create table [tb]([co11] int,[col2] varchar(3))insert [tb]select 35,'AAA' union allselect 47,'AAA' union allselect 51,'AAA' union allselect 36,'BBB' union allselect 35,'BBB' union allselect 47,'BBB'--------------开始查询--------------------------select [col1]=stuff((select ','+ltrim([co11]) from tb  where col2=t.col2 for xml path('')), 1, 1, '') ,col2from tb tgroup by col2 ----------------结果----------------------------/* col1                                                                                                                                                                                                                                                             col2---------------------------------------------------------------------------------------------------------------- ----35,47,51                                                                                                                                                                                                                                                         AAA36,35,47                                                                                                                                                                                                                                                         BBB(2 行受影响)*/