怎样让一个string成员自动编号解决方案

怎样让一个string成员自动编号
TICPP的一道题目
我用stringstream做出来了，就是如果

C/C++ code

ss << "Bird #" <<Bird::i; //注意，Bird和#中间有一个空格ss >> name;

name就只有Bird了，不能够自动编号了。
请问怎么办，还有啥别的方法吗？
/*
14. Write a class called Bird that contains a string member
and a static int. In the default constructor, use the int to
automatically generate an identifier that you build in the
string, along with the name of the class (Bird #1, Bird #2,
etc.). Add an operator<< for ostreams to print out the
Bird objects. Write an assignment operator= and a copyconstructor.
In main( ), verify that everything works
correctly.
*/

C/C++ code

 
 #include <iostream> 
 #include <sstream> 
 #include <string> 
 using namespace std; 
  
 class Bird { 
 string name; 
 static int i; 
 public: 
 Bird(){ 
 Bird::i++; 
 stringstream ss; 
 ss  < < "Bird#"  < <Bird::i; 
 ss >> name; 
 } 
 Bird(const Bird& obj) { 
 Bird::i++; 
 name = "copyed from " + obj.name; 
 } 
 friend ostream& operator < <(ostream& os, const Bird& obj) { 
 os  < < obj.name; 
 return os; 
 } 
 const Bird operator=(const Bird& obj) { 
 Bird::i++; 
 name = "assigned from " + obj.name; 
 return *this; 
 } 
 }; 
  
 int Bird::i = 0; 
  
 int main() { 
 Bird o1; 
 cout  < < o1  < < endl; 
 Bird o2; 
 cout  < < o2  < < endl; 
 o2 = o1; 
 cout  < < o2  < < endl; 
 Bird o3(o2); 
 cout  < < o3  < < endl; 
 } 
 

[解决办法]
for(int x=0;x<1000;x++){
char sz[32]={0};
sprintf("Bird #%d",i);
cout<<sz;
}
[解决办法]

C/C++ code

Bird(){        Bird::i++;        stringstream ss;        ss << "Bird#" <<Bird::i;        name=ss.str();    } 

 

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