C语言实现URL字符串的分割,该如何处理

C语言实现URL字符串的分割
以下是代码，gcc编译出现
错误：expected ‘;’ before ‘{’ token 请大家帮我看下，我不知道问题到底出在哪里了，先谢了！！！



#include <stdio.h>
#include <string.h>
#include <stdlib.h>

//#define MAX_PER_LINE 100


char* url_parting(char* buf)
{
  int i=0;
  char *url;
  int len = strlen(buf);
  printf("%d\n",len);
  printf("in the url_parting\n");
  while(i<len-1)
  {
  if(buf[i] != '/')
  {
  url[i] = buf[i];
  }
  else
  {
  if(buf[i] == '/' && buf[i+1]!='/')
  {
  url[i] = '\n';
  }
  else(buf[i] == '/' && buf[i+1]=='/')
  {
  url[i]=buf[i];
  url[++i]=buf[i];
  }
  }
  i++;
  }
  url[i+1] = '\0';
  printf("end of url_parting\n");
  return url;
}


int main()
{
  //char str[100] = "http://www.youku.com/kjfi/jfi/gil";
  char *str;
  scanf("%s",str);
  printf("in the main\n");
  char* str1 = url_parting(str);
  printf("%s\n",str1);
  return 0;
}

[解决办法]
else(buf[i] == '/' && buf[i+1]=='/')
漏掉if了吧？
[解决办法]

C/C++ code

#include <iostream>using namespace std;#include <stdio.h>#include <string.h>#include <stdlib.h>//#define MAX_PER_LINE 100char* url_parting(char* buf){  int i=0;  char *url;  int len = strlen(buf);  printf("%d\n",len);  printf("in the url_parting\n");  while(i<len-1)  {      if(buf[i] != '/')      {          url[i] = buf[i];      }      else      {          if(buf[i] == '/' && buf[i+1]!='/')          {              url[i] = '\n';          }          else if(buf[i] == '/' && buf[i+1]=='/')//这里少了if          {              url[i]=buf[i];              url[++i]=buf[i];          }      }      i++;  }  url[i+1] = '\0';  printf("end of url_parting\n");  return url;}int main(){  //char str[100] = "http://www.youku.com/kjfi/jfi/gil";  char *str;  scanf("%s",str);  printf("in the main\n");  char* str1 = url_parting(str);  printf("%s\n",str1);  return 0;}