这个如何运行不成？请哪位大侠帮一下，多谢

这个怎么运行不成？请哪位大侠帮一下，谢谢！
public class Employee{
  private int id;
  private String name;
  private String department;
  private double salary;
  public String getDepartment(){
  return department;
  }
  public void setDepartment(String department){
  this.department=department;
  }
  public int getId(){
  return id;
  }
  public void setId(int id){
  this.id=id;
  }
  public String getName(){
  return name;
  }
  public void setName(){
  this.name=name;
  }
  public double getSalary(){
  return salary;
  }
  public void setSalary(double salary){
  this.salary=salary;
  }
}

[解决办法]
java应用程序要运行必须要有public static void main(String[])类型的主函数入口，你这个程序没有，所以无法运行
给你贴个能跑的

Java code

public class Employee{    private int id;    private String name;    private String department;    private double salary;    public String getDepartment(){        return department;    }    @Override    public String toString() {        return "Employee{" +                "id=" + id +                ", name='" + name + '\'' +                ", department='" + department + '\'' +                ", salary=" + salary +                '}';    }    public void setDepartment(String department){        this.department=department;    }    public int getId(){        return id;    }    public void setId(int id){        this.id=id;    }    public String getName(){        return name;    }    public void setName(String name){        this.name=name;    }    public double getSalary(){        return salary;    }    public void setSalary(double salary){        this.salary=salary;    }    public static void main(String[] args){          Employee e=new Employee();          e.setId(1);          e.setName("demo1");          e.setSalary(1000.0);          System.out.println(e);    }}