window.open参数的问题
<script Language= "JavaScript ">
function processForm(form){
var type;
if (xf> 70) type = "A ";
if (xf <60 && xf> 50) type = "B ";
if (xf <40 && xf> 30) type = "C ";
if (xf <20 && xf> 10) type = "D ";
if (xf <10) type = "E ";
window.open( "frank.asp?Type= "+ type , "aaa ", " ")
} </script>
为什么TYPE参数传过去结果是undefined？
[解决办法]
因为xf是undefined,if里面的判断都是false,所以type也是undefined
