js 怎么取两段日期之间的所有天的日期值

高分求教 js 如何取两段日期之间的所有天的日期值
例如 startday=2009-12-1 ,endday=2010-3-31,
我要的days=“2009-12-1，2009-12-2，2009-12-3.......2010-3-30,2010-3-31” ,
请大家帮忙，在线等，
要求用js实现

[解决办法]

JScript code

<script>d1 = new Date(2009,11,1)d2 = new Date(2010,2,31)s = []days = (Date.parse(d2)-Date.parse(d1))/1000/60/60/24for(i = 0;i<=days;i++){d =  new Date(2009,11,1+i)d = d.getFullYear() + "-" + (d.getMonth()+1) + "-" + d.getDate()s.push(d)}document.write(s.join("<br/>"))</script>
[解决办法]
JScript code
//YYYY-MM-DD格式输入function Todo(begin, end){    var ab = begin.split("-");    var ae = end.split("-");    var db = new Date();    db.setFullYear(ab[0], ab[1]-1, ab[2]);    var de = new Date();    de.setFullYear(ae[0], ae[1]-1, ae[2]);    var a = [];    for (var i=0,temp=db;temp < de;i++)    {        a[i] = GetDate(temp);        temp.setTime(temp.getTime() + 24*60*60*1000);    }    a[i] = GetDate(de);    return a.join();}//返回1900-01-01格式的字符串function GetDate(d){    return d.getFullYear() + "-" + (d.getMonth()+1) + "-" +  d.getDate();}document.write(Todo("2009-12-31", "2010-03-31"));
[解决办法]
探讨

JScript code
<script>
d1 = new Date(2009,11,1)
d2 = new Date(2010,2,31)
s = []
days = (Date.parse(d2)-Date.parse(d1))/1000/60/60/24
for(i = 0;i<=days;i++)
{
d =  new Date(2009,11,1+i)
d = d.g……

[解决办法]
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