计算二进制文件的字符数
本人写了一个读取文件中字符数的c程序,在unix系统下编译和运行.读txt等文件时正常,但是在读取二进制文件时候与要求输出不符.请大家帮我看一下问题
#include <stdio.h>
#include <stdlib.h>
#include <ctype.h>
int main(){
unsigned int puncNum = 0;
unsigned int whiteSpaceNum = 0;
unsigned int otherNum = 0;
unsigned int totalNum = 0;
char ch = 0;
FILE *fp = fopen( "valgrind.log ", "r ");
if(fp == NULL){
fclose(fp);
exit(EXIT_FAILURE);
}
else {
while((ch = getc(fp)) != EOF)
{
if(isspace(ch))
whiteSpaceNum++;
else if(ispunct(ch))
puncNum++;
else otherNum++;
}
fclose(fp);
totalNum = whiteSpaceNum + puncNum + otherNum;
printf( "%u punctuation characters\n ",puncNum);
printf( "%u whitespace characters\n ",whiteSpaceNum);
printf( "%u other characters\n ",otherNum);
printf( "Total: %u characters\n ",totalNum);
return EXIT_SUCCESS;
}
}
要求输出的是
8121 punctuation characters
1494 whitespace characters
55921 other characters
Total: 65536 characters
我的输出是
26 punctuation characters
5 whitespace characters
204 other characters
Total: 235 characters
fopen的第二个参数我试过 "r "和 "rb ",结果是一样的
[解决办法]
因为 2 进制文件中可能读取结果会出现 EOF，
所以用 while((ch = getc(fp)) != EOF) 判断可能会提前结束，
导致数目不对。
