vb6，正则表达式怎么同时把( )之间和< >之间的文字（并保留它们在原来段落中的顺序）提取出来？
比如一段文字（仅作为举例，实际比这个复杂）：
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guaranteed<索马里>, while reaffirming(美国) its goal of developing nuclear power as a clean energy source.
Hu extends condolences to Myanmar
Chinese President Hu Jintao has delivered a message of condolences （利比亚）to his Myanmar counterpart U Thein Sein over the losses <东部>of life and property inflicted by a strong earthquake.
UnionPay network works well: chairman
China doesn't <us> need another interbank network for credit cards, said the board chairman of China UnionPay Co Ltd - the country's only credit card network - in response to an anti-monopoly request from the United States to the World Trade Organization (WTO).
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我想把所有<>和（）中的字符给提取出来（并且要保留它们原先在段落中的顺序，所以不能说分两次单独提取），即结果是：索马里美国利比亚东部usWTO
单独提取（）中的文字用regex.Pattern = "（([\s\S]*?)）" 就可以了。我现在等于要regex.Pattern = "（([\s\S]*?)）" 或者"<([\s\S]*?)>" 。要怎么写呢？我试了regex.Pattern = "（([\s\S]*?)）"|"<([\s\S]*?)>"不对。
正则表达式多个pattern的“或者”是怎么写的呢？
多谢！！
[解决办法]
Set reg = New RegExp
reg.Global = True
s = "guaranteed<索马里>, while reaffirming(美国) i{完美}ts "
reg.Pattern = "<(.*?)>|\((.*?)\)|\{(.*?)\}"
For Each r In reg.execute(s)
rv = rv & reg.Replace(r.Value, "$1$2$3") & vbCrLf
Next
MsgBox rv
