关于表单和js的问题
<meta http-equiv= "Content-Type " content= "text/html; charset=gb2312 " />
<script language= "javascript ">
function show4(obj,str){
var td = document.getElementById(str);
if(checkBoxId.checked == true){
td.style.display = "block ";
}else{
td.style.display = "none ";
}
}
</script>
<body>
<form>
<table width= "75% " border= "1 ">
<tr>
<td width= "23% "> 1.什么是医疗保险
<input type= "checkbox " name= "checkbox " id= "checkBoxId " onclick= "show4(this, 'show1 ') "/> </td>
<td width= "77% " id= "show1 " style= "display:none "> <select name= "select ">
<option> 11111111 </option>
<option> 2222222222 </option>
<option> 33333333 </option>
</select> </td>
</tr>
</table>
</form>
这个为什么我给form去掉，就可以用啊，不去掉就不能用
[解决办法]
<meta http-equiv= "Content-Type " content= "text/html; charset=gb2312 " />
<script language= "javascript ">
function show4(obj,str){
var td = document.getElementById(str);
if(document.getElementById( "checkbox ").checked == true){
document.getElementById( "show1 ").style.display = "block ";
}else{
document.getElementById( "show1 ").style.display = "none ";
}
}
</script>
<body>
<form>
<table width= "75% " border= "1 ">
<tr>
<td width= "23% "> 1.什么是医疗保险
<input type= "checkbox " name= "checkbox " id= "checkbox " onClick= "show4(this, 'show1 ') "/> </td>
<td width= "77% "> <div id= "show1 " style= "display:none "> <select name= "select ">
<option> 11111111 </option>
<option> 2222222222 </option>
<option> 33333333 </option>
</select> </div> </td>
</tr>
</table>
</form>
