如何在ajax中刷新多个数据 - Web 开发 / Ajax
<html><head><title>E1_2</title><script type="text/javascript">var xmlHttpfunction showHint(){ xmlHttp=GetXmlHttpObject() if(xmlHttp==null) { alert ("您的浏览器不支持AJAX!"); return; } var C_url="gethint.asp"; C_url=C_url+"?q="+"CAlarm_State"; C_url=C_url+"&sid="+Math.random(); xmlHttp.onreadystatechange=stateChanged; xmlHttp.open("GET",C_url,true); xmlHttp.send(null); var t=setTimeout("GetState()",1000)}function stateChanged(){ if(xmlHttp.readyState==4) { document.getElementById("C_State").src=xmlHttp.responseText; }}function GetXmlHttpObject(){ var xmlHttp=null; try { xmlHttp=new XMLHttpRequest(); } catch(e) { try { xmlHttp=new ActiveXObject("Msxml2.XMLHTTP"); } catch(e) { xmlHttp=new ActiveXObject("Microsoft.XMLHTTP"); } } return xmlHttp;}</script></head><body onload=showHint()><form method=POST action=><table border="0" width="200" cellspacing="4" cellpadding="4"><tr><td align="center" width="100"><font size="5">MTP-001</font></td><td> </td></tr><tr><td align="center" width="100"><img border="0" id="H_State" width="24" height="24"> <img border="0" id="C_State" width="24" height="24"></td><td><p align="right"> <input type="submit" value=RUN name=run> <input type="submit" value=STOP name=stop></td></tr><tr><td align="center" width="100"><b><font size="5">H C</font></b></td><td align="center"><input type="submit" value=CLR name=clr></td></tr></table></form></html>
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