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同样的做法在VS2003下可以运行,为什么在VS2005下不能运行,请(C#中也有发贴子)

2012-02-08 
同样的做法在VS2003下可以运行,为什么在VS2005下不能运行,请高手指点(C#中也有发贴子)同样的做法在VS2003

同样的做法在VS2003下可以运行,为什么在VS2005下不能运行,请高手指点(C#中也有发贴子)
同样的做法在VS2003下可以运行,为什么在VS2005下不能运行,请高手指点
操作步骤:
拖一个ComboBox   到窗体上命名为ComboBoxName
进入代码     导入命名空间
vb.net为:   Imports   System.Data.SqlClient
c#为:using   System.Data.SqlClient;
vb.net2003下的代码为:

'   匯入命名空間
Imports   System.Data.SqlClient
Public   Class   Form1
        Inherits   System.Windows.Forms.Form
        '   CurrencyManager   物件的類別層級宣告
        Dim   bmFoxStudio   As   BindingManagerBase

'     这里是Windows   窗体设计器生成的代码,,就省了。
        Private   Sub   Form1_Load(ByVal   sender   As   System.Object,   ByVal   e   As   System.EventArgs)   Handles   MyBase.Load
                Me.ComboBoxName.DataSource   =   CreateDataSource()
                ComboBoxName.DisplayMember   =   "id "
                bmFoxStudio   =   Me.BindingContext(CreateDataSource())
        End   Sub
        Private   Function   CreateDataSource()   As   ICollection
                Dim   dt   As   New   DataTable
                Dim   dr   As   DataRow
                dt.Columns.Add(New   DataColumn( "id ",   GetType(Int32)))
                dt.Columns.Add(New   DataColumn( "PkID ",   GetType(String)))
                For   i   As   Integer   =   0   To   5
                        dr   =   dt.NewRow()
                        dr(0)   =   i
                        dr(1)   =   "破晓之阳 "
                        dt.Rows.Add(dr)
                Next
                Dim   dv   As   New   DataView(dt)
                Return   dv
        End   Function

        Private   Sub   ComboBoxName_SelectedIndexChanged(ByVal   sender   As   System.Object,   ByVal   e   As   System.EventArgs)   Handles   ComboBoxName.SelectedIndexChanged
                bmFoxStudio.Position   =   Me.ComboBoxName.SelectedIndex
        End   Sub
End   Class

vb.net2005   代码:
Imports   System.Data.SqlClient
Public   Class   Form1
        Dim   bmFoxStudio   As   BindingManagerBase

        Private   Sub   Form1_Load(ByVal   sender   As   System.Object,   ByVal   e   As   System.EventArgs)   Handles   MyBase.Load
                Me.ComboBoxName.DataSource   =   CreateDataSource()


                ComboBoxName.DisplayMember   =   "id "
                bmFoxStudio   =   Me.BindingContext(CreateDataSource())
        End   Sub
        Private   Function   CreateDataSource()   As   ICollection
                Dim   dt   As   New   DataTable
                Dim   dr   As   DataRow
                dt.Columns.Add(New   DataColumn( "id ",   GetType(Int32)))
                dt.Columns.Add(New   DataColumn( "PkID ",   GetType(String)))
                For   i   As   Integer   =   0   To   5
                        dr   =   dt.NewRow()
                        dr(0)   =   i
                        dr(1)   =   "破晓之阳 "
                        dt.Rows.Add(dr)
                Next
                Dim   dv   As   New   DataView(dt)
                Return   dv
        End   Function
        Private   Sub   ComboBoxName_SelectedIndexChanged(ByVal   sender   As   System.Object,   ByVal   e   As   System.EventArgs)   Handles   ComboBoxName.SelectedIndexChanged
                bmFoxStudio.Position   =   Me.ComboBoxName.SelectedIndex
        End   Sub
End   Class

c#.net2003代码:
//   CurrencyManager   物件的類別層級宣告
BindingManagerBase   bmFoxStudio;
private   void   ComboBoxName_SelectedIndexChanged(object   sender,   System.EventArgs   e)
{
bmFoxStudio.Position   =   ComboBoxName.SelectedIndex;
}

private   void   Form1_Load(object   sender,   System.EventArgs   e)
{
ComboBoxName.DataSource   =   CreateDataSource(   );
ComboBoxName.DisplayMember   =   "id ";
                        bmFoxStudio   =   this.BindingContext[CreateDataSource(   )];
}
ICollection   CreateDataSource(   )
{
DataTable   dt   =   new   DataTable();
DataRow   dr;
dt.Columns.Add(new   DataColumn( "id ",   typeof(Int32)));
dt.Columns.Add(new   DataColumn( "PkID ",   typeof(string)));
for   (int   i   =   0;   i   <   6;   i++)
{
dr   =   dt.NewRow();
dr[0]   =   i;
dr[1]   =   "破晓之阳 ";
dt.Rows.Add(dr);
}
DataView   dv   =   new   DataView(dt);
return   dv;
}
c#.net2005   代码就省略了。




------解决方案--------------------


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