效率有关问题

效率问题
这段代码可以优化吗，就是迭代一个list，把当中的对象的属性设到另外一个对象的属性上，再把另外的对象add到另外一个list中。上代码：

A.java

Java code

public class A {    private String abc;    private int a;    private float ab;        public String getAbc() {        return abc;    }    public void setAbc(String abc) {        this.abc = abc;    }    public int getA() {        return a;    }    public void setA(int a) {        this.a = a;    }    public float getAb() {        return ab;    }    public void setAb(float ab) {        this.ab = ab;    }}

Java code

private String abc;    private int a;    private float ab;        public String getAbc() {        return abc;    }    public void setAbc(String abc) {        this.abc = abc;    }    public int getA() {        return a;    }    public void setA(int a) {        this.a = a;    }    public float getAb() {        return ab;    }    public void setAb(float ab) {        this.ab = ab;    }

Java code

public class C {    /**     * @param args     */    public static void main(String[] args) {        // TODO Auto-generated method stub        List<A> alist = new ArrayList<A>();        List<B> blist = new ArrayList<B>();                A a1 = new A();        a1.setA(1);        a1.setAb(1.1f);        a1.setAbc("111");                A a2 = new A();        a2.setA(2);        a2.setAb(1.2f);        a2.setAbc("222");                A a3 = new A();        a3.setA(3);        a3.setAb(1.3f);        a3.setAbc("333");                alist.add(a1);        alist.add(a2);        alist.add(a3);                for(A a:alist){ // 此处是否可以优化，或者其他方法。其中A.java 和B.java属性方法都一样的，就类名不一样。            B b = new B();            b.setA(a.getA());            b.setAb(a.getAb());            b.setAbc(a.getAbc());            blist.add(b);        }                for(B b:blist){            System.out.println(b.getA());            System.out.println(b.getAb());            System.out.println(b.getAbc());        }            }}