字段中相同数据的区分开,求相同数据的第一条解决方法

字段中相同数据的区分开,求相同数据的第一条

SQL code

CREATE TABLE [dbo].[Wound](    [WoundID] [int] IDENTITY(1,1) NOT NULL,    [Winding] [varchar](50) NULL,        [TF_ID] [int] NULL, CONSTRAINT [PK_Wound] PRIMARY KEY CLUSTERED (    [WoundID] ASC)WITH (PAD_INDEX  = OFF, STATISTICS_NORECOMPUTE  = OFF, IGNORE_DUP_KEY = OFF, ALLOW_ROW_LOCKS  = ON, ALLOW_PAGE_LOCKS  = ON) ON [PRIMARY]) ON [PRIMARY]GOinsert into Wound values('NP1',1)insert into Wound values('NP1',1)insert into Wound values('NP2',1)insert into Wound values('NP3',1)insert into Wound values('NP2',1)insert into Wound values('NP3',2)insert into Wound values('NP3',2)insert into Wound values('NP1',2)insert into Wound values('NP1',2)

我想要的结果是
WoundID Winding TF_ID
1 NP1 1
3 NP2 1
4 NP3 1
6 NP2 2
8 NP1 2 
不用ROW_NUMBER() over(partition by........
服务器的数据是2000的， 求解


[解决办法]

SQL code

select * from Wound T where not exists (select 1 from Wound where T.[Winding]=[Winding] and T.[TF_ID]=[TF_ID] And T.[WoundID]>[WoundID] ) 

 

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