如何使TreeView子节点的Check状态与父节点一致？顶者有分！
这段代码是树的代码，能够选择当前节点的check时子节点的状态和父节点一样。
我想加一点功能就是让子节的check为false时，父节点的check为false
但我不懂jscript，不知在哪加
<script type= "text/jscript ">
function client_OnTreeNodeChecked()
{
var obj = window.event.srcElement;
var treeNodeFound = false;
var checkedState;
if (obj.tagName == "INPUT " && obj.type == "checkbox ")
{
var treeNode = obj;
checkedState = treeNode.checked;
do
{
obj = obj.parentElement;
}
while (obj.tagName != "TABLE ")
var parentTreeLevel = obj.rows[0].cells.length;
var parentTreeNode = obj.rows[0].cells[0];
var tables = obj.parentElement.getElementsByTagName( "TABLE ");
var numTables = tables.length
if (numTables > = 1)
{
for (i=0; i < numTables; i++)
{
if (tables[i] == obj)
{
treeNodeFound = true;
i++;
if (i == numTables)
{
return;
}
}
if (treeNodeFound == true)
{
var childTreeLevel = tables[i].rows[0].cells.length;
if (childTreeLevel > parentTreeLevel)
{
var cell = tables[i].rows[0].cells[childTreeLevel - 1];
var inputs = cell.getElementsByTagName( "INPUT ");
inputs[0].checked = checkedState;
}
else
{
return;
}
}
}
}
}
}
</script>
[解决办法]
好的.帮顶!^-^
[解决办法]
<script type= "text/jscript "> function UncheckParent (obj) { while(obj != null) { var tagName = obj.tagName.toLowerCase(); if(tagName == "div " && obj.id == "TreeView1 ") { return; } if( tagName== "table ") { var checkBox = obj.getElementsByTagName( "INPUT "); if(checkBox.length > 0) { checkBox[0].checked = false; } obj = obj.parentElement.previousSibling; }else obj = obj.parentElement; } } function client_OnTreeNodeChecked() { var obj = window.event.srcElement; var treeNodeFound = false; var checkedState; if (obj.tagName == "INPUT " && obj.type == "checkbox ") { var treeNode = obj; checkedState = treeNode.checked; if(!checkedState) { UncheckParent(obj); } do { obj = obj.parentElement; } while (obj.tagName != "TABLE ") var parentTreeLevel = obj.rows[0].cells.length; var parentTreeNode = obj.rows[0].cells[0]; var tables = obj.parentElement.getElementsByTagName( "TABLE "); var numTables = tables.length if (numTables > = 1) { for (i=0; i < numTables; i++) { if (tables[i] == obj) { treeNodeFound = true; i++; if (i == numTables) { return; } } if (treeNodeFound == true) { var childTreeLevel = tables[i].rows[0].cells.length; if (childTreeLevel > parentTreeLevel) { var cell = tables[i].rows[0].cells[childTreeLevel - 1]; var inputs = cell.getElementsByTagName( "INPUT "); inputs[0].checked = checkedState; } else { return; } } } } } } </script>
[解决办法]
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